Help with binomial approximation
Okay so they've asked using the binomial expansion found in part a
approximate 7100^1/3
the original equation is (8-9x)^1/3
how do i get the value of x i need to sub into the expansion
i thought since theyre the same power i could just make them equal to find the value of x but this yields the wrong answer
approximate 7100^1/3
the original equation is (8-9x)^1/3
how do i get the value of x i need to sub into the expansion
i thought since theyre the same power i could just make them equal to find the value of x but this yields the wrong answer
Original post by DedeM9
Okay so they've asked using the binomial expansion found in part a
approximate 7100^1/3
the original equation is (8-9x)^1/3
how do i get the value of x i need to sub into the expansion
i thought since theyre the same power i could just make them equal to find the value of x but this yields the wrong answer
approximate 7100^1/3
the original equation is (8-9x)^1/3
how do i get the value of x i need to sub into the expansion
i thought since theyre the same power i could just make them equal to find the value of x but this yields the wrong answer
The binomial approximation is only valid for hence for . This is why your approach yields the wrong answer - your value is out of this range!
Instead, try rewriting .
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