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    can someone explain C ii
    This is cie s13 41 q5 btw
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    Magnetic flux linkage is nba (number of turns x magnetic field strength, given by b multiplied by the area of cross section of the wire )

    First calculate b for the formula they give and then multiply by n and a
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    Sorry I read the wrong part of the question , for part c use emf = - nba all divided by t .
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    If you are wondering why current is reversed it’s just a case of lenz’s law . So putting the magnet into the coil it will induce a like pole (north) but taking the magnet back out the coil towards the left will induce an opposite pole (South Pole ) on the coil . So the induced current flows in opposite direction to the change in the magnetic flux that produced it . The change in magnetic flux that produced it was simply the motion of the magnet . The fact we are changing the direction of the motion of the magnet causes there to be this reversal in current direction
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