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AS maths question help

Hi, could someone please help with this:

A bird leaves its nest at time t = 0 for a short flight along a straight line. The bird then returns to its nest. The bird is modelled as a particle moving in a straight horizontal line. The distance, s metres, of the bird from its nest at time t seconds is given by s = 1/10 (t^4 20t^3 + 100t^2), where 0 t ≤10 (a) Explain the restriction, 0 t≤ 10.

I really dont understand this question. could someone help please?
Original post by Bertybassett
Hi, could someone please help with this:

A bird leaves its nest at time t = 0 for a short flight along a straight line. The bird then returns to its nest. The bird is modelled as a particle moving in a straight horizontal line. The distance, s metres, of the bird from its nest at time t seconds is given by s = 1/10 (t^4 20t^3 + 100t^2), where 0 t ≤10 (a) Explain the restriction, 0 t≤ 10.

I really dont understand this question. could someone help please?


Well, the bird flies away from its nest and comes back. How far away is the bird when t=0t=0? So the restriction must mean that...?
Original post by RDKGames
Well, the bird flies away from its nest and comes back. How far away is the bird when t=0t=0? So the restriction must mean that...?


well it would be zero metres away? but i dont get what im meant to write for 3 marks.
Reply 3
Find the roots of this function. Time can't be negative, to start with, hence t0t \geq 0. If it flies away and comes back its overall displacement is 0 as well and can't be negative, so the function only applies until then.
Original post by Bertybassett
well it would be zero metres away? but i dont get what im meant to write for 3 marks.


Yeah, though I meant t=10t=10.

You just need to say that the restriction is when the function is +ve, so this covers the entire journey of the bird.

Distance cannot be -ve by definition, so must only count the function where it's +ve.
Original post by Bertybassett
Hi, could someone please help with this:

A bird leaves its nest at time t = 0 for a short flight along a straight line. The bird then returns to its nest. The bird is modelled as a particle moving in a straight horizontal line. The distance, s metres, of the bird from its nest at time t seconds is given by s = 1/10 (t^4 20t^3 + 100t^2), where 0 t ≤10 (a) Explain the restriction, 0 t≤ 10.

I really dont understand this question. could someone help please?

Part a:
When t = 0, s = 0 too. That means Displacement is 0 when the bird is at rest.
When t = 10, s = 0 again. That means the bird flew for 10 seconds and came back to the nest in 10 seconds, therefore the displacement is 0 as it returned.

Part b:
S = 1/10(t⁴-20t³+100t²)
Expand the brackets and get s = 1/10t⁴-2t³+10t²
Differentiate S to get v, because the velocity is 0 when the bird first comes to rest.
ds/dt = 2/5t³-6t²+20t
So v = 2/5t³-6t²+20t
Put v = 0:
2/5t³-6t²+20t = 0
t = 0, t = 5 and t = 10
T must be 5 because the other two values of t are when the bird is at rest and when the bird comes back.
Substitute in the value of t = 5 into the S equation:
s = 1/10((5)⁴-20(5)³+100(5)²) = 62.5m

You're welcome 😂❤️
Reply 6
Original post by Shamsul.17
Original post by Shamsul.17
Part a:



You're welcome


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