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How to do this I am having a mental breakdown :frown:

Rearrange the formula to get z:

4z^3 = (x^1/2 y^-3 z)^2 ÷ (y^-5)
Original post by Revision Boiii
How to do this I am having a mental breakdown :frown:

Rearrange the formula to get z:

4z^3 = (x^1/2 y^-3 z)^2 ÷ (y^-5)


do you have an answer for this. i tried to do it and got an answer but it looks a bit dodgy
:frown:
just divide both sides by z^2, youre left with 4z on the left hand side

e: then simplify ofc
Reply 4
Original post by adsuudixfra
just divide both sides by z^2, youre left with 4z on the left hand side

e: then simplify ofc


What if z were 0?
Original post by Sataris
What if z were 0?


if z is 0 then all x and y satisfy the equation, its obviously implicit that division by z is acceptable, theres no reason to be an arse
Reply 6
Original post by adsuudixfra
if z is 0 then all x and y satisfy the equation, its obviously implicit that division by z is acceptable, theres no reason to be an arse


"it's obviously implicit that division by 0 is acceptable"

is what you're saying right now
Original post by Sataris
"it's obviously implicit that division by 0 is acceptable"

is what you're saying right now


its like a sub gcse question dude, do you really think its worth confusing someone clearly stressed?
Original post by Revision Boiii
How to do this I am having a mental breakdown :frown:

Rearrange the formula to get z:

4z^3 = (x^1/2 y^-3 z)^2 ÷ (y^-5)


GCSE grade 9 AQA CGP book? I’ll attempt this and post an answer when I have my laptop back (bc can’t write all mathsy)
ill do it when i come back from skl
Original post by adsuudixfra
just divide both sides by z^2, youre left with 4z on the left hand side

e: then simplify ofc


this should work OK
(edited 5 years ago)

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