# Mole, mass calculations. Watch

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Hi,

Can someone explain how to do this question? I've tried it but keep reaching a dead end...

Thanks!

Can someone explain how to do this question? I've tried it but keep reaching a dead end...

Thanks!

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#2

(Original post by

Hi,

Can someone explain how to do this question? I've tried it but keep reaching a dead end...

Thanks!

**020200**)Hi,

Can someone explain how to do this question? I've tried it but keep reaching a dead end...

Thanks!

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#4

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Is this a gcse question, seems like it. I might give it a go. It isn't as complicated as it seems though.

**Iahmed512**)Is this a gcse question, seems like it. I might give it a go. It isn't as complicated as it seems though.

**020200**)

Hi,

Can someone explain how to do this question? I've tried it but keep reaching a dead end...

Thanks!

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#5

**020200**)

Hi,

Can someone explain how to do this question? I've tried it but keep reaching a dead end...

Thanks!

This mass would only make 95% of 550g. Meaning that you would need to calculate the mass of NaNH2 needed for 577.5%, which would give u 550g, since 550g is 95% of 577.5.

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#6

Hi! So I just tried this question on paper, and I have checked that my answer is in fact correct.

This is how I did it:

1. If 95% yield is going to give us 550g then we should know how much we are making at 100% yield as that is the real amount we will make in the reaction

2. To work out 100% yield, you can divide 550 by 95 then multiply by 100...should give you 578.94...

3.Now we use mole formula to work out the number of moles this 100% amount is

4. So do your answer for 100% yield divided by the molar mass of NaN3 which should be 65, and this should give you an answer of 8.906... moles

5. The ratio of NaNH2: NaN3 is 2:1, therefore, you should multiply your mole answer for NaN3 by 2 to get moles of NaNH2 you must make, you should get 17.81... moles

6. Now once again use mole formula to work out mass

7. Mass= No of moles x Mr so then you should be doing 17.81... x 78 to get 1389.47...

8. This answer is now your answer to 2NaNH2

9. We divide the answer by 2 because the ration there is 2:1 and we only want it for 1 moles

The final answer should be 694.7g

Sorry if this method is long winded or complicated, but this is how I approached it. Always make sure to keep your full answers in your calculator, do not round until the end because otherwise, your answer will not be accurate.

This is how I did it:

1. If 95% yield is going to give us 550g then we should know how much we are making at 100% yield as that is the real amount we will make in the reaction

2. To work out 100% yield, you can divide 550 by 95 then multiply by 100...should give you 578.94...

3.Now we use mole formula to work out the number of moles this 100% amount is

4. So do your answer for 100% yield divided by the molar mass of NaN3 which should be 65, and this should give you an answer of 8.906... moles

5. The ratio of NaNH2: NaN3 is 2:1, therefore, you should multiply your mole answer for NaN3 by 2 to get moles of NaNH2 you must make, you should get 17.81... moles

6. Now once again use mole formula to work out mass

7. Mass= No of moles x Mr so then you should be doing 17.81... x 78 to get 1389.47...

8. This answer is now your answer to 2NaNH2

9. We divide the answer by 2 because the ration there is 2:1 and we only want it for 1 moles

The final answer should be 694.7g

Sorry if this method is long winded or complicated, but this is how I approached it. Always make sure to keep your full answers in your calculator, do not round until the end because otherwise, your answer will not be accurate.

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#8

(Original post by

No. This is from the AQA old specification A-Level Unit 1 Papers.

**020200**)No. This is from the AQA old specification A-Level Unit 1 Papers.

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#9

(Original post by

What have you tried? Do you know the two equations needed to do the question?

**marupe**)What have you tried? Do you know the two equations needed to do the question?

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#10

(Original post by

Hi! So I just tried this question on paper, and I have checked that my answer is in fact correct.

This is how I did it:

1. If 95% yield is going to give us 550g then we should know how much we are making at 100% yield as that is the real amount we will make in the reaction

2. To work out 100% yield, you can divide 550 by 95 then multiply by 100...should give you 578.94...

3.Now we use mole formula to work out the number of moles this 100% amount is

4. So do your answer for 100% yield divided by the molar mass of NaN3 which should be 65, and this should give you an answer of 8.906... moles

5. The ratio of NaNH2: NaN3 is 2:1, therefore, you should multiply your mole answer for NaN3 by 2 to get moles of NaNH2 you must make, you should get 17.81... moles

6. Now once again use mole formula to work out mass

7. Mass= No of moles x Mr so then you should be doing 17.81... x 78 to get 1389.47...

8. This answer is now your answer to 2NaNH2

9. We divide the answer by 2 because the ration there is 2:1 and we only want it for 1 moles

The final answer should be 694.7g

Sorry if this method is long winded or complicated, but this is how I approached it. Always make sure to keep your full answers in your calculator, do not round until the end because otherwise, your answer will not be accurate.

**Sneedshelp**)Hi! So I just tried this question on paper, and I have checked that my answer is in fact correct.

This is how I did it:

1. If 95% yield is going to give us 550g then we should know how much we are making at 100% yield as that is the real amount we will make in the reaction

2. To work out 100% yield, you can divide 550 by 95 then multiply by 100...should give you 578.94...

3.Now we use mole formula to work out the number of moles this 100% amount is

4. So do your answer for 100% yield divided by the molar mass of NaN3 which should be 65, and this should give you an answer of 8.906... moles

5. The ratio of NaNH2: NaN3 is 2:1, therefore, you should multiply your mole answer for NaN3 by 2 to get moles of NaNH2 you must make, you should get 17.81... moles

6. Now once again use mole formula to work out mass

7. Mass= No of moles x Mr so then you should be doing 17.81... x 78 to get 1389.47...

8. This answer is now your answer to 2NaNH2

9. We divide the answer by 2 because the ration there is 2:1 and we only want it for 1 moles

The final answer should be 694.7g

Sorry if this method is long winded or complicated, but this is how I approached it. Always make sure to keep your full answers in your calculator, do not round until the end because otherwise, your answer will not be accurate.

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#11

(Original post by

Hey just a heads up for next time, try not to post a full solution as it doesn't help the student as much as getting them to do it themselves

**marupe**)Hey just a heads up for next time, try not to post a full solution as it doesn't help the student as much as getting them to do it themselves

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Hi,

I am just trying to get it right in my head. Is this correct:

So, 8.46 moles of NaN

My only problem is that none of this takes into account N

I am just trying to get it right in my head. Is this correct:

So, 8.46 moles of NaN

_{3 }are produced if there is a yield of 95%. Therefore there is 16.92 x 100/95 moles of NaNH_{2 }required to make the 100% yield?My only problem is that none of this takes into account N

_{2}O, therefore how can the calculation be accurate?
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#13

(Original post by

Hi,

I am just trying to get it right in my head. Is this correct:

So, 8.46 moles of NaN

My only problem is that none of this takes into account N

**020200**)Hi,

I am just trying to get it right in my head. Is this correct:

So, 8.46 moles of NaN

_{3 }are produced if there is a yield of 95%. Therefore there is 16.92 x 100/95 moles of NaNH_{2 }required to make the 100% yield?My only problem is that none of this takes into account N

_{2}O, therefore how can the calculation be accurate?Your numbers are right but 8.46 moles is for 100% yield, not the 95. We have to only consider the maximum yield which is 100%. It does not have to take into account N2O at all because that is just something else that is reacting. Look at the question again, it is just asking how much NaNH2 is needed.I think you are over-analyzing it, so do not worry about anything else apart from the two things they ask you about.

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#14

(Original post by

But the student has already tried the question and cannot do it, so surely running through it step by step will help them see where they've gone wrong? I doubt they reached out to student room to then be told do it yourself.

**Sneedshelp**)But the student has already tried the question and cannot do it, so surely running through it step by step will help them see where they've gone wrong? I doubt they reached out to student room to then be told do it yourself.

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#15

(Original post by

My only problem is that none of this takes into account N

**020200**)My only problem is that none of this takes into account N

_{2}O, therefore how can the calculation be accurate?
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