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Free radical substitution.

Hi,

Can someone help me on this free radical substitution question? I've been looking over my notes but can't see how the equation matches the principles in my text book and notes. Can someone please explain? Does it have anything to do with the fact that UV light is absent, or am I on the wrong track?

Thanks!
Screen Shot 2018-04-28 at 17.19.09.png70.5KB
Original post by 020200
Hi,

Can someone help me on this free radical substitution question? I've been looking over my notes but can't see how the equation matches the principles in my text book and notes. Can someone please explain? Does it have anything to do with the fact that UV light is absent, or am I on the wrong track?

Thanks!


You are not asked for the mechanism, simply the equation for the reaction.
Original post by 020200
Hi,

Can someone help me on this free radical substitution question? I've been looking over my notes but can't see how the equation matches the principles in my text book and notes. Can someone please explain? Does it have anything to do with the fact that UV light is absent, or am I on the wrong track?

Thanks!


This is a reaction where there's excess of something.

It's the same procedure as normal, except you got a chlorine in the alkane.

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