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Why is +6 the oxidation state of Cr in CrO2F2?
I understand that F is -1. But why is oxygen -2 in this case? I thought it became +2 when in compound with fluorine?
I understand that F is -1. But why is oxygen -2 in this case? I thought it became +2 when in compound with fluorine?
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#2
The O is bonded to Cr, not F. The more electronegative element (O) is assigned a negative oxidation number. Hence O has a negative oxidation number
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(Original post by BobbJo)
The O is bonded to Cr, not F. The more electronegative element (O) is assigned a negative oxidation number. Hence O has a negative oxidation number
The O is bonded to Cr, not F. The more electronegative element (O) is assigned a negative oxidation number. Hence O has a negative oxidation number
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#4
(Original post by anactualmess)
Do you mind further elaborating on the structure of CrO2F2 please? I'm still a bit confused
Do you mind further elaborating on the structure of CrO2F2 please? I'm still a bit confused
The F is not bonded to O
Here's a useful link
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(Original post by BobbJo)
The central Cr atom is covalently bonded to 2 O atoms and 2 F atoms.
The F is not bonded to O
Here's a useful link
The central Cr atom is covalently bonded to 2 O atoms and 2 F atoms.
The F is not bonded to O
Here's a useful link
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#6
(Original post by anactualmess)
Okay, thank you! So is the oxidation state of oxygen on +2 when it is in the compound OF2?
Okay, thank you! So is the oxidation state of oxygen on +2 when it is in the compound OF2?
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