anactualmess
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Why is +6 the oxidation state of Cr in CrO2F2?

I understand that F is -1. But why is oxygen -2 in this case? I thought it became +2 when in compound with fluorine?
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username3249896
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The O is bonded to Cr, not F. The more electronegative element (O) is assigned a negative oxidation number. Hence O has a negative oxidation number
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anactualmess
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(Original post by BobbJo)
The O is bonded to Cr, not F. The more electronegative element (O) is assigned a negative oxidation number. Hence O has a negative oxidation number
Do you mind further elaborating on the structure of CrO2F2 please? I'm still a bit confused
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username3249896
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(Original post by anactualmess)
Do you mind further elaborating on the structure of CrO2F2 please? I'm still a bit confused
The central Cr atom is covalently bonded to 2 O atoms and 2 F atoms.

The F is not bonded to O

Here's a useful link
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anactualmess
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(Original post by BobbJo)
The central Cr atom is covalently bonded to 2 O atoms and 2 F atoms.

The F is not bonded to O

Here's a useful link
Okay, thank you! So is the oxidation state of oxygen on +2 when it is in the compound OF2?
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username3249896
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(Original post by anactualmess)
Okay, thank you! So is the oxidation state of oxygen on +2 when it is in the compound OF2?
Yes since F is more electronegative than O
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