# Electric field strenth question

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#1
why are the charges the same?
E=v/d
and graph goes negative as it approaches sphere so surely the spheres are opposite charged?
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#2
(Original post by assassinbunny123)
why are the charges the same?
E=v/d
and graph goes negative as it approaches sphere so surely the spheres are opposite charged?
question
0
2 years ago
#3
(Original post by assassinbunny123)
why are the charges the same?
E=v/d
and graph goes negative as it approaches sphere so surely the spheres are opposite charged?
What is the graph? It would be good that you attach the graph.

(Original post by assassinbunny123)
question
What is the question?
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#4
(Original post by Eimmanuel)
What is the graph? It would be good that you attach the graph.

What is the question?
here is the question.
the graph i already posted previously
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2 years ago
#5
(Original post by assassinbunny123)
here is the question.
the graph i already posted previously
This is a nice question!

Hint: The sign of the electric field strength indicates the direction (left or right) a charged test particle would move if placed between the two spheres.
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#6
(Original post by theOldBean)
This is a nice question!

Hint: The sign of the electric field strength indicates the direction (left or right) a charged test particle would move if placed between the two spheres.
By nice question do u mean easy?
the sign of E at x=0 is positive at x=6 its negative
so doesn't that mean that sphere A is positive charged and sphere B is negatively charged depending on what the charge of P is? EITHER way doesn't that mean they have opposite signs?
i mean if it was same charge then wouldn't the graph be in the shape of y=x^2
or am i getting confused with the graph of electric potential?

i also attached the markscheme
0
2 years ago
#7
(Original post by assassinbunny123)
By nice question do u mean easy?
the sign of E at x=0 is positive at x=6 its negative
so doesn't that mean that sphere A is positive charged and sphere B is negatively charged depending on what the charge of P is? EITHER way doesn't that mean they have opposite signs?
i mean if it was same charge then wouldn't the graph be in the shape of y=x^2
or am i getting confused with the graph of electric potential?

i also attached the markscheme

I think you forget that electric field strength is a vector.

Say for example A is positively charged and sphere B is negatively charged
The electric field vector due A on the right side of A will be pointing to right and the electric field vector due B on the left side of sphere B will be pointing to right also.
The electric field strength would reinforce along the points between Sphere A and B.
There is no way for the electric field strength be zero as shown by the graph.
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