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    Let’s put this group for discussing math , the exam is tmr , we can discuss here , who else has exam tmr
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    I've got an exam tomorrow too, along with IT Theory
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    I have my exam tomorrow. Anyone has the paper of Feb 2018 ?
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    (Original post by DiptoBiswas)
    I have my exam tomorrow. Anyone has the paper of Feb 2018 ?
    I couldn’t find that paper
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    (Original post by SpeedDemon918)
    I've got an exam tomorrow too, along with IT Theory
    What do u guys find difficult ? How many past papers have u done and which years
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    i found this question about sequences and i don’t seem to know how to continue any further. “The sum of the first n terms of an arithmetic progression is 1/2(3n 7). Find the first term and the common difference of the progression.” Any help would be appreciated xx (btw reference is nov.17 paper 12)
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    (Original post by Universecolors)
    I couldn’t find that paper
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    (Original post by 1234123456785678)
    i found this question about sequences and i don’t seem to know how to continue any further. “The sun of the first n terms of an arithmetic progression is 1/2(3n+7). Find the first term and the common difference of the progression.” This is what i’ve done so far but i’m not sure how to eliminate any of the variables. Any help would be appreciated xx (btw reference is nov.17 paper 12)
    If a_n is the sequence, and S_n the sum, then S_n = a_1 + a_2 + ... + a_n.

    So, what do you get if you calculate S_n - S_{n-1}?
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    (Original post by DFranklin)
    If a_n is the sequence, and S_n the sum, then S_n = a_1 + a_2 + ... + a_n.

    So, what do you get if you calculate S_n - S_{n-1}?
    a_n?
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    (Original post by 1234123456785678)
    a_n?
    Yes. So since you are given a formula for S_n, you can find a formula for a_n. Once you have a_n, then a_1 is the first term, and a_k - a_{k-1} should equal the same thing for any choice of k and be the common difference.
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    (Original post by DFranklin)
    Yes. So since you are given a formula for S_n, you can find a formula for a_n. Once you have a_n, then a_1 is the first term, and a_k - a_{k-1} should equal the same thing for any choice of k and be the common difference.
    Do u guys feel like ur prepared ? Idk for me , how many past papers did u guys do : (
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    (Original post by Universecolors)
    Do u guys feel like ur prepared ? Idk for me , how many past papers did u guys do : (
    Kind of pointless asking me. I graduated almost 30 years ago.
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    I have the Feb 2018 paper but I don't have the mark scheme
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    Which exam board is this?
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    Here is the question paper
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  1. File Type: pdf 03_9709_12___2RP.pdf (139.1 KB, 22 views)
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    (Original post by DFranklin)
    Yes. So since you are given a formula for S_n, you can find a formula for a_n. Once you have a_n, then a_1 is the first term, and a_k - a_{k-1} should equal the same thing for any choice of k and be the common difference.
    oooh thank you!!
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    (Original post by Greenapplepear)
    Which exam board is this?
    CIE
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    (Original post by SpeedDemon918)
    Here is the question paper
    You posting??
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    (Original post by Helisls)
    You posting??
    Doesn't it work ??
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    (Original post by Helisls)
    You posting??
    https://www.docdroid.net/q6ACSTz/03-9709-12-2rp.pdf
 
 
 
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