ABCD is a rhombus such that the coordinates of A are (1, 1) and AC → = (6 ) 2 Given that the diagonals of the rhombus intersect at the point P, find the coordinates of P. help me how to solve this please !!
YES IT'S (4,2) HOW ? it's from igcse math b june 2017!
So I assumed that A to C was across. The P is intersected by both diagonals, so it should be the centre. From A to P, it should be half way to C, as it's in the centre. You have the vector (6,2), the top number is the number to the left right(right is positive, left is negative). The number 2 dictates whether it will go up or down(up is positive, down is negative). Since p is half A to C, you gotta half the vector which is the length of the line from A going to C. So you add 3 to the X coordinate and 1 to the Y coordinate.
So I assumed that A to C was across. The P is intersected by both diagonals, so it should be the centre. From A to P, it should be half way to C, as it's in the centre. You have the vector (6,2), the top number is the number to the left right(right is positive, left is negative). The number 2 dictates whether it will go up or down(up is positive, down is negative). Since p is half A to C, you gotta half the vector which is the length of the line from A going to C. So you add 3 to the X coordinate and 1 to the Y coordinate.