Qer
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is this equation valid?

for aluminium aqua complex with excess OH-


Al(H2O)3(0H)3 + 3 OH- ---> [Al(OH)6]^3- + 3 H20
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Qer
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charco
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Kian Stevens
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Yes the equation is valid. OH- ligands always seem to substitute H2O ligands.

That pesky OH-...
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Qer
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(Original post by Kian Stevens)
Yes the equation is valid. OH- ligands always seem to substitute H2O ligands.

That pesky OH-...
But my book show's it forms Al (OH)^-4
When aluminium react with excess ammonia
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Kian Stevens
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(Original post by Qer)
But my book show's it forms Al (OH)^-4
When aluminium react with excess ammonia
I don't do the AQA specification so my mileage may vary with this question.

However, reacting with excess ammonia will substitute water ligands for ammonia ligands. Ammonia only acts as a source of OH- ions when it's added dropwise, not in excess.

I can't think of any way how you'd form [Al(OH)4]- from your starting position by reacting with excess ammonia, or anything for that matter.
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