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    I've been doing practice questions for Thursdays exam and i cam across this:
    Chlorine, bromine and iodine are in group 7 of the periodic table.
    The order of reactivity of these three elements can be shown by carrying out displacement experiments.
    You are given
    potassium bromide solution
    potassium chloride solution
    potassium iodide solution
    bromine solution
    chlorine solution
    iodine solution
    Describe how these solutions could be used to carry out experiments to show the order of reactivity of bromine, chlorine and iodine, explaining how the results would show the order of reactivity.
    you may use calculations of you wish. [6 marks]
    I'm not sure where to start, please help!
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    Remember: when you've got a halogen bonded with potassium (or any of the other alkali metals really), if you introduce a more reactive halogen, it will displace the old less reactive halogen. So if you add chlorine to potassium iodide, because chlorine is more reactive than iodine, it will displace the iodine and you're left with potassium chloride and iodine. If you add any less reactive halogen, nothing happens. So the more reactive the halogen, the less reactive its ion is.

    So you would just throw together different salt solutions and halogens to see what displaces what.
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    (Original post by Sinnoh)
    Remember: when you've got a halogen bonded with potassium (or any of the other alkali metals really), if you introduce a more reactive halogen, it will displace the old less reactive halogen. So if you add chlorine to potassium iodide, because chlorine is more reactive than iodine, it will displace the iodine and you're left with potassium chloride and iodine. If you add any less reactive halogen, nothing happens. So the more reactive the halogen, the less reactive its ion is.

    So you would just throw together different salt solutions and halogens to see what displaces what.
    Thank you!
 
 
 
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