# s3 need help to find estimate maximum value X

#1
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#2
value for k=2/3 and bias is alpha/2
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#3
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#4
is it becuase the continuous distribution is (a-3,2a+3)
so max will be 2a+3 and minimum will be a-3
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3 years ago
#5
(Original post by assassinbunny123)
is it becuase the continuous distribution is (a-3,2a+3)
so max will be 2a+3 and minimum will be a-3
No.

You don't know how the max/min of the sample relates to the max/min of the poplulation.

There is however a statistic you've can derive from the sample that you do know about. What is it?
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#6
not really I'm confused now
. how is my reasoning wrong in this case. in part b Y=KX where y is an unbiased estimator of a.
we found k to be 2/3. this question says that a random sample of 10 from X is taken where this sample follows the same distribution. I did
a=k(xbar)
where k =2/3 and X bar in this case is 8 hence
a=16/3 and then substitute it into the interval.
is this not a correct method, Im worried now since you out right rejected my solution. 😔
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3 years ago
#7
(Original post by assassinbunny123)
not really I'm confused now
. how is my reasoning wrong in this case. in part b Y=KX where y is an unbiased estimator of a.
we found k to be 2/3. this question says that a random sample of 10 from X is taken where this sample follows the same distribution. I did
a=k(xbar)
where k =2/3 and X bar in this case is 8 hence
a=16/3 and then substitute it into the interval.
is this not a correct method, Im worried now since you out right rejected my solution. 😔

What you've just posted is the correct method.
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#8
(Original post by ghostwalker)

What you've just posted is the correct method.
0
3 years ago
#9
(Original post by assassinbunny123)
You've just used it. X-bar is the statistic you've derived from the sample.
0
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