Simultaneous Hyperbolics - Solved

Just use, the definitions for Cosh x, sinh x etc in exponential form and it should be easy to proceed from there.

Have you worked it all through?

I get:

1. $e^x + e^{-x} - 3e^y + 3e^{-y} = 0$

2. $e^x - e^{-x} + 3e^y + 3e^{-y} = 5$

Where do I go from there?

Got there now. Made a lil mistake that threw the whole thing off. Thanks!

by using $\sqrt{1+\sinh^2 x}$

you get the first equation from:
coshX - 3sinhY = 0

to:
$\sqrt{1+\sinh^2 x} = 3sinhy$

Then you can work it so that you make $sinh^2x$ the subject.

Re-arrange the 2nd equation so you can make sinhx the subject. Substitute. Finally use the $Sinh^2x + Cosh^2x = 1$ to get rid of the squared functions. Use the log equations to work out their values.