Question:
A stone is thrown vertically upwards with the speed 15m/s from a point h above the ground
The stone hits the ground 4 seconds later
(a) Find the value of h
This is a typical question and I went about it by doing
s = -h
u = 15
a = -g
t = 4
Subbed the values into s = ut + 1/2at^2 to get the answer.
My question:
Why do you sub in t = 4 if s = -h shouldn't it be some value less than 4? It shouldn't take 4 seconds to travel h to the ground.
Thank You