At first thoughts, this is gonna come from sin^2(theta) + cos^2(theta) = 1, then replace a sin(theta) and a cos(theta) by right-angled trig values. (eg sin(theta) = opposite/hypotenuse). Draw yourself a diagram if there isn't one already.
Draw straight lines at each vertex, perpendicular to the corridor, so that it looks like a tipped rectangle in a box.
There will now be four triangles surrounding the table. Mark in which of the angles are equal to theta (using sum of angles on a straight line, z angles, etc.), and see if you can work out any more of the sides of the triangles (in terms of theta) using basic trig.
draw lines perpendicular to the hall walls against the corners of the table. find the angles that equal theta and then take the unknown lengths to be X and 130-X
you can know for equations and rearrange them to equal x
they havnt tho, one has sed their answer is wrong and i dont understand the other one.... any help please????!!!?
Read post #5. If it still doesn't make sense, give us a more detailed explanation of what doesn't make sense. We avoid giving out full solutions, so without more information on which part you don't understand we can't actually help you.
draw lines perpendicular to the hall walls against the corners of the table. find the angles that equal theta and then take the unknown lengths to be X and 130-X
you can know for equations and rearrange them to equal x
I solve it as you say but didn't find the right answer.