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OCR AS Maths (A) Pure and Mechanics - 23/05/18 [Exam Discussion] watch

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1. Leave any thoughts, feelings and answers about the exam here. How do you think you did?
2. I think I might move to Australia and never look at my grade
3. Not enough time to get it all done
4. I know!! I was rushing all of it so I couldn’t concentrate properly and get the right answer
5. (Original post by Stressedoutxxx)
I think I might move to Australia and never look at my grade
That's how I feel about my Further Mechanics exam.

6. I got the exponential one correct at first and then spent 20 more minutes on it and changed the value of A

OH one more now

the pulley one, I got the answer and then crossed it out.

FINE 17 MARKS
7. (Original post by vivienne0402)

I got the exponential one correct at first and then spent 20 more minutes on it and changed the value of A

OH one more now

the pulley one, I got the answer and then crossed it out.

FINE 17 MARKS
8. (Original post by Thanu123)
a=100, k=-ln 0.6 and something... I can't remember
9. (Original post by vivienne0402)
a=100, k=-ln 0.6 and something... I can't remember
a was 75, not 100.

100 = 25+ae^-kt
t= 0 therefore
100 = 25+ae^0
100 = 25+ a*1
100= 25 + a
a= 75
10. (Original post by Name Name123)
a was 75, not 100.

100 = 25+ae^-kt
t= 0 therefore
100 = 25+ae^0
100 = 25+ a*1
100= 25 + a
a= 75
I got 75 too
11. (Original post by Name Name123)
a was 75, not 100.

100 = 25+ae^-kt
t= 0 therefore
100 = 25+ae^0
100 = 25+ a*1
100= 25 + a
a= 75
OMG
then i get it right now...
ALL my friends told me it was 100
yeah!!! thank you so much
12. does anyone remember the equations of the tangent one?
13. What did you get for the value of k for the exponential?
14. (Original post by vivienne0402)
does anyone remember the equations of the tangent one?
I think it was 5y + x=k and 4y +10 = x^2 ?
15. (Original post by Thanu123)
I think it was 5y + x=k and 4y +10 = x^2 ?
How did you find the answer to that?
16. (Original post by Stressedoutxxx)
How did you find the answer to that?
Dunno if this is right but it was my best guess..
5y= k-x
y= 1/5(k-x)
y= -1/5(x-k) (in the form of y-y1 = m(x=x1)) therefore gradient = -1/5

x^2+4y= 10
4y= 10-x^2
y= 10/4 - 1/4 x^2
dy/dx = -1/2x

-1/5 = -1/2x
x= -2/5
which also = k since k is the x coordinate of the intersection
17. (Original post by Name Name123)
Dunno if this is right but it was my best guess..
5y= k-x
y= 1/5(k-x)
y= -1/5(x-k) (in the form of y-y1 = m(x=x1)) therefore gradient = -1/5

x^2+4y= 10
4y= 10-x^2
y= 10/4 - 1/4 x^2
dy/dx = -1/2x

-1/5 = -1/2x
x= -2/5
which also = k since k is the x coordinate of the intersection
Guess i lost 5 marks then😧😊
18. (Original post by Thanu123)
Guess i lost 5 marks then😧😊
To be honest, I don't think what I did was correct.
19. For the exponential question what did you get for k?

Since ky = gradient, I got 75k = 15 so k = 0.2

For the tangent question, I got k = -12.7 by using the following method:

sub in to other equation:

then since it is a tangent, there is one point of intersection so just one root hence b^2 - 4ac = 0

20. (Original post by rikkiardo)
For the exponential question what did you get for k?

Since ky = gradient, I got 75k = 15 so k = 0.2

For the tangent question, I got k = -12.7 by using the following method:

sub in to other equation:

then since it is a tangent, there is one point of intersection so just one root hence b^2 - 4ac = 0

so k = -12.7
I think this is the right solution, cheers.

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