1i) stem and leaf diagram
ii) Negatively skewed
iii) Median = 8.4
Midrange = 7.7
iv) Median isn't effected by extreme values, midrange is
2i)
3i) P (L and D) = 0.05
ii) Diagram, L section was 0.03, D section was .2, intersection was 0.05
L and D were not independent because P(L and D) was not equal to P(L) * P(D). (0.05 is not equal to 0.06)
4i) 1/33
ii
QUESTION NUMBERS/LETTERS ARE BIT CONFUSING, please help
5i)
A) 25C12 = 5200300
B)14C6 * 11C6 = 1387386
ii A2*(0.7 * 0.3) * 2(0.25)^2 + 2(0.75*0.25)*2(0.3)^2 = 0.12 or other people got 0.21. Not sure! I got it wrong myself by squaring instead
iii) 2*(0.7 * 0.3)/2*(0.7 * 0.3) * 2(0.25) + 2(0.75*0.25)+2(0.3)
or 0.125 as some people got, not sure either I got this wrong
6i) With 20 and 6 - Accept H0 reject h1
6ii) With 100 and 41 - Accept H1 and reject H0
7i) a = 10
ii) 80% below 111 bpm
iii) Mean was 72.2, standard deviation was 13.6
iv) Outliers above and below the mean.
v) 18 year olds positively skewed, 4 years old normal distribution, slightly negatively skewed
Modal group in 18 year olds was higher than 4 year old
Median in 18 year olds is lower than 4 year olds