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Physics Help

Can anyone get this ?
answer is 9.6 × 10−13 m
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Original post by splitter2017
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Yea sure just hold on a sec
It will be very nice of you if you could solve this one https://ibb.co/hMqiDJ too :biggrin:
Original post by Black.Panther00
It will be very nice of you if you could solve this one https://ibb.co/hMqiDJ too :biggrin:

Hi
I agree with the answer you gave
First you need to find the total energy of the system by adding the kinetic to the mass energy (E=mc^2)- beware the units of the mass...
Convert to joules
and then divide by two and use E=(hc)/lambda to find the wavelength

My answer is for the first btw, although the same approach would work for the second one too
(edited 5 years ago)
Original post by clareeey
Hi
I agree with the answer you gave
First you need to find the total energy of the system by adding the kinetic to the mass energy (E=mc^2)- beware the units of the mass...
Convert to joules
and then divide by two and use E=(hc)/lambda to find the wavelength

My answer is for the first btw, although the same approach would work for the second one too


Could you explain the mark-scheme?
https://ibb.co/igTmYJ
I've had a go and have gotten 8.33×10−13 m for the wavelengthPhysics Question.jpg
Original post by Black.Panther00
Could you explain the mark-scheme?
https://ibb.co/igTmYJ


I take it this is the markscheme for the second question

The first thing it does it find the mass of all the formed particles, it does this assuming they are stationary because that will require the minimum KE of the protons to start with.

This relates to the total amount of energy that the protons have to start with. The mass of the 2 protons is subtracted to give the mass/ kinetic energy they have to start with.

Each proton will have half of this KE
Original post by MatthewWatson24
I've had a go and have gotten 8.33×10−13 m for the wavelengthPhysics Question.jpg


Check your calculation of 1/2 ET. You have 2.38 which isn't half of your ET. Everything else looks fine
Original post by MatthewWatson24
I've had a go and have gotten 8.33×10−13 m for the wavelengthPhysics Question.jpg


For part c here is the correct working:


The answer given above is not correct. They made a mistake when halving the energy released.

https://imgur.com/a/R5TmEQh
Original post by clareeey
I take it this is the markscheme for the second question

The first thing it does it find the mass of all the formed particles, it does this assuming they are stationary because that will require the minimum KE of the protons to start with.

This relates to the total amount of energy that the protons have to start with. The mass of the 2 protons is subtracted to give the mass/ kinetic energy they have to start with.

Each proton will have half of this KE


Ahan okay i got it now , The only thing iam confuse in is How is Mev/C^2 value the same for MeV value ? :/
Original post by splitter2017
For part c here is the correct working:


The answer given above is not correct. They made a mistake when halving the energy released.

https://imgur.com/a/R5TmEQh


Thanks Alot
Original post by MatthewWatson24
I've had a go and have gotten 8.33×10−13 m for the wavelengthPhysics Question.jpg


Thank you too :smile:
Original post by Black.Panther00
Ahan okay i got it now , The only thing iam confuse in is How is Mev/C^2 value the same for MeV value ? :/


Its is because of the units they specified for the mass
I've tried to explain it on paper. Let me know if it helps
One thing to always remember if that the units on both sides of an equation have to be the same
Original post by clareeey
Its is because of the units they specified for the mass
I've tried to explain it on paper. Let me know if it helps
One thing to always remember if that the units on both sides of an equation have to be the same


ahannnnnnnnnn !!!!!!!!!!!!! I got ittttt Thank youu sooo much :smile: , May god bless

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