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# Differentiation watch

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1. Could you give me a step-by-step on this differentiation:

differentaite;
1/(√(x+1))

thank you.
2. Its just the chain rule.

3. (Original post by insparato)
Its just

But then its going to become way too complex;

-0.5(x+1)^-0.75(0.5(x+1)-1.5)

surely this is wrong???
4. Firstly if n = -0.5 what is (n-1) ? Apart from that the n(f(x)^{n-1}) term is correct.

Secondly the f'(x) term I do not know where you get getting that from, if f(x) = x+1 then f'(x) is simply?
5. (Original post by TheLoneRanger)
But then its going to become way too complex;

-0.5(x+1)^-0.75(0.5(x+1)-1.5)

surely this is wrong???
Buh?

You're differentiating . Take a deep breath and dive straight in - it's not as hard as it looks. (How would you differentiate (x+1)^3?)
6. yes basically using chain rule, use the power "-1/2" instead of the square root and hopefully you will see how to apply the chain rule.
7. (Original post by generalebriety)
Buh?

You're differentiating . Take a deep breath and dive straight in - it's not as hard as it looks. (How would you differentiate (x+1)^3?)
Ok, overcomplicating it arent it , i just got it
8. (x+1)^-0.5

let u = x+1

dy/dx = -0.5(x+1)^-1.5

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