Copper from malachite GCSE Watch

Loser222
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How do i do theorteical yeiled and actual yield and percentage yield of copper from malachite

I used 10g of malachite
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martin101
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right Im assuming that you started off with pure malachite which is Cu2CO3(OH)2. therefore you know that for every molecule of malachite you process you get 2 molecules of copper or to put it another way every mole of malachite used makes two moles of copper.

Im assuming you know about moles and basic mole calculations (they are sort of the top end of GCSE - but are the only way to do this problem)

THEORETICAL YIELD

Moles of malachite = mass/Mr = 10/(63.5*2+12+16*3+2(16+1)) = 4.52*10^-2mol
as moles of malachite=1/2moles copper,
Moles copper = 4.52*10^-2 *2 = 9.04*10^-2mol
Ar Cu=63.5 therefore:
Expected mass Cu= 63.5*9.04*10^-2=5.75g

ACTUAL YIELD
whatever mass of copper you end up with

PERCENTAGE YIELD
actual mass/expected mass *100 should do the trick

Check some of my numbers (particularly the Ar values) as I didnt check them very well.

I will probably get into trouble from my peers for just doing the question for you, however I see no other simple way of showing you what to do!

Now... gief rep :P
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