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#2
Set gravitational potential energy = specific heat capacity energy (assumes no thermal energy is transferred and also as the stream is continuous kinetic energy is likely constant so gpe goes straight to heat)
i.e mgh=mcΔθ and solve for θ
Energy gained by the water is not dependent on the mass as you can see the mass cancels from either side of the equation
i.e mgh=mcΔθ and solve for θ
Energy gained by the water is not dependent on the mass as you can see the mass cancels from either side of the equation
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#3
The specific heat capacity of the water:
where C = 4200Jkg-1K-1
m = mass
is the temperature changeE = gravitational potential energy = mgh
and is the energy supplied to the water falling through a height of 100m
rearranging for
substituting for E = mgh
and plugging in the values:
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#5
As no thermal energy, also E = mgh
So mgh = mcΔθ
gh = cΔθ
Δθ=gh / c
you know what height, specific heat capacity and gravitational field strength are, so u have enough information.
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