AQA A Level Biology Paper 2 - 11th June 2018 Unofficial Markscheme

For the 1st question, I talked about high temperatures causing the stomata to close therefore preventing carbon dioxide from entering and combining with RuBP to make 2xGP. Since they highlighted light-dependent reaction.

Don’t agree with the division one. My answer was 1+2^83. There were 84 total divisions but You have to consider there is only 1 cell to begin with. Think my final answer was something like 9.67 x10^24 or something like that

I know but if they’re autosomal linked only two gametes are produced; AB ab? If you do a genetic cross possible genotypes were AABB AaBb and aabb, which didn’t match with the phenotypes?
Dunno maybe I’m just being stupid 😭

I put some garbage abou an addition mutation to another gene causing a frame shift which conincisentky meant it was now the gene that codes for lactase production

My answer for hardy weinberg was 43%

did anyone get 18% for the hardy weinburg q??

What ratio did people get for the dihybrid cross

I put some garbage abou an addition mutation to another gene causing a frame shift which conincisentky meant it was now the gene that codes for lactase production

I said there was a mutation in a gene which is responsible for regulating the expression of the lactase gene, so the lactase is not methylated when humans start eating other stuff...
Yours sounds more like aqa's cup of tea, though.

Think I chatted bs, but I wrote about it mutating the gene that codes for the transcription factor for the gene so the gene is not transcribed ;/ (ik thats probs 0 marks)

ur right bro. 9.67x10^24. there was aq like that in bio paper 1. you have to take one off the power

Did anyone else find that the question regarding dihybrid inheritance didn’t make sense, it said that the genes were on the same chromosome( surely meaning autosomal linkage) but then I couldn’t see how 4 different phenotypes were produced when they’re autosomal linked

I thought that too but the question was so sneaky, it said if it was not linked but it was not in bold or anything. So it was basically a normal Di hibrid cross with 9:3;3;1

For the lactase one I think I said that there is a gene that coded for a protein that could produce a TF for the lactase enzyme, would that be wrong

9:3:3:1 but I had no clue 😭

The genes were not linked so woudlnt it of been 1:1:1:1 ratio?

Don’t agree with the division one. My answer was 1+2^83. There were 84 total divisions but You have to consider there is only 1 cell to begin with. Think my final answer was something like 9.67 x10^24 or something like that