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Maths GCSE question helppp

please can someone help me with this question:

Make a the subject of the formula.


P = n^2 +a /n +a
Original post by rose_gurney
Multiply everything by n, move the n^3 term to the LHS and divide both sides by (n 1) to get a= (Pn-n^3)/(n 1)


Im still confused when multiplying by n on both side will it give: pn=n^2 + a /a but then dont the a's cancel out each other :frown:
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Avatar for suf1.
suf1.
13
Original post by Maryam_Osman
please can someone help me with this question:

Make a the subject of the formula.


P = n^2 +a /n +a


Multiply both sides by (n+a) so you get Pn + Pa = n^2 + a

Subtract a from both sides so you get Pn + Pa - a = n^2

Subtract Pn from both sides so you get Pa - a = n^2 - Pn

Factorise the left side so you get a(P - 1) = n^2 - Pn

Divide both sides by (P - 1) so you get a = n^2 - Pn / P - 1
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Avatar for hg.13
hg.13
6
Original post by Maryam_Osman
please can someone help me with this question:

Make a the subject of the formula.


P = n^2 +a /n +a


Step 1) PN + PA = N^2 + A

Step 2) PA - A = N^2 - PN

Step 3) A(P - 1) = N^2 - PN

Step 4) A = N^2 - PN / P - 1

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