Sonia2598
Badges: 13
Rep:
?
#1
Report Thread starter 2 years ago
#1
How did everyone find the paper today?
0
reply
anonymous123_7
Badges: 7
Rep:
?
#2
Report 2 years ago
#2
Decent, not sure about the two 6 markers tho
1
reply
Roe123
Badges: 9
Rep:
?
#3
Report 2 years ago
#3
It was fine but I think it was quite hard
0
reply
NityanV
Badges: 3
Rep:
?
#4
Report 2 years ago
#4
My will to live has never been so low
3
reply
Roe123
Badges: 9
Rep:
?
#5
Report 2 years ago
#5
How did you guys answer the question on the experiment to carry out the rate of hydrolysis for halogenoalkane?
0
reply
hannan_999
Badges: 0
Rep:
?
#6
Report 2 years ago
#6
what did you lot write for the synthetic route from benzene to phenylethene
0
reply
rbunny98
Badges: 7
Rep:
?
#7
Report 2 years ago
#7
(Original post by Roe123)
How did you guys answer the question on the experiment to carry out the rate of hydrolysis for halogenoalkane?
honestly **** knows, i started talking bout gas syringe
0
reply
Lisande
Badges: 4
Rep:
?
#8
Report 2 years ago
#8
(Original post by rbunny98)
honestly **** knows, i started talking bout gas syringe
Hahhaha so did I
0
reply
Roe123
Badges: 9
Rep:
?
#9
Report 2 years ago
#9
(Original post by hannan_999)
what did you lot write for the synthetic route from benzene to phenylethene
1. React benzene with enthanoyl chloride to form the ketone
2. The ketone can form to secondary alcohol by using LiAlH4
3. The alcohol can form into alkene by using conc. H3PO4 catalyst
1
reply
Dddaaaavxjd hs
Badges: 2
Rep:
?
#10
Report 2 years ago
#10
What do you guys got for Activation Energy from slope? I found it to be very small
0
reply
Roe123
Badges: 9
Rep:
?
#11
Report 2 years ago
#11
(Original post by rbunny98)
honestly **** knows, i started talking bout gas syringe
I talked about recording the time for the precipitate to form such as AgCl, AgBr, AgI and carry out the rate by 1/T... Hope the grade boundary is lower than last year
0
reply
Roe123
Badges: 9
Rep:
?
#12
Report 2 years ago
#12
(Original post by Dddaaaavxjd hs)
What do you guys got for Activation Energy from slope? I found it to be very small
I got positive 2 hundred sth...
0
reply
hannan_999
Badges: 0
Rep:
?
#13
Report 2 years ago
#13
(Original post by Roe123)
1. React benzene with enthanoyl chloride to form the ketone
2. The ketone can form to secondary alcohol by using LiAlH4
3. The alcohol can form into alkene by using conc. H3PO4 catalyst
omg same but the LiAlH4 in dry ether conditions and for the fist part the halogen carrier is AlCl3
0
reply
Roe123
Badges: 9
Rep:
?
#14
Report 2 years ago
#14
(Original post by Dddaaaavxjd hs)
What do you guys got for Activation Energy from slope? I found it to be very small
gradient = -8 - 0/ 1.7(sth like that) x 10^-3 - 1.395 x 10^-3
gradient calculated is negative and use gradient = Ea/R
0
reply
Roe123
Badges: 9
Rep:
?
#15
Report 2 years ago
#15
(Original post by hannan_999)
omg same but the LiAlH4 in dry ether conditions and for the fist part the halogen carrier is AlCl3
Yes, I also used the same reagent with you
0
reply
Sonia2598
Badges: 13
Rep:
?
#16
Report Thread starter 2 years ago
#16
(Original post by Roe123)
I talked about recording the time for the precipitate to form such as AgCl, AgBr, AgI and carry out the rate by 1/T... Hope the grade boundary is lower than last year
I did that too!
0
reply
rbunny98
Badges: 7
Rep:
?
#17
Report 2 years ago
#17
-2000 for gradient or na
0
reply
ZoeLilo
Badges: 1
Rep:
?
#18
Report 2 years ago
#18
(Original post by Roe123)
How did you guys answer the question on the experiment to carry out the rate of hydrolysis for halogenoalkane?
i talked about the silver nitrate test and how long it took to form a precipitate - halogenoalkanes don't dissolve in water so you add ethanol
im not sure tho
0
reply
Roe123
Badges: 9
Rep:
?
#19
Report 2 years ago
#19
(Original post by rbunny98)
-2000 for gradient or na
for the gradient, its -26229 sth = -Ea/ 8.31

so -26229sth x 8.31 = -Ea

so the Ea is 217962.99 Jmol-1

so divide it by 1000 to get 217.96 sth in kJmol-1 for the Ea
1
reply
ZoeLilo
Badges: 1
Rep:
?
#20
Report 2 years ago
#20
(Original post by Roe123)
gradient = -8 - 0/ 1.7(sth like that) x 10^-3 - 1.395 x 10^-3
gradient calculated is negative and use gradient = Ea/R
i got a positive gradient of 100 something kj
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

With no certainty that exams next year will take place, how does this make you feel?

More motivated (86)
31.27%
Less motivated (189)
68.73%

Watched Threads

View All