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Edexcel AS Mathematics: Statistics S1- 13 June 2018: Unofficial Mark Scheme.

Poll

how was it?

1a) a = 0.2
b = 0.6
c = 0.1
1b) F(7) = 0.9

spinner:
a = 0.1
b = 0.35
E(Y) = 4
Var(Y) = 63.9?
P(Y>X) = 0.55

histogram question:
2.5 width and 2.4 height
median 7.46
mean 8.115
skew: 0.5

bead question:
P(bead = green) = 1/32
P(two reds given one is red) = 5/37

4.a) P(µ < X < 17) = 0.1
b. 0.441

regression:
t = 17.7 - 0.0126h
17.7 degrees at sea level
change: -1.89 degrees

7a) P(B < 92) = 11.51%
7b) P(B>Q3) = 0.2215
7c) Q1 = 123g
7d) 3/16
(edited 5 years ago)

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1. a. a=0.2 b=0.6 c=0.1
b. 0.9
p0tatoEs
Am I a farmer Edexcel?
For the last question with bettys potatoes should be 6(0.25x0.25x0.5) since there were 6 arrangements of the possible potatoes
Original post by Mario Manalu
1. a. a=0.2 b=0.6 c=0.1
b. 0.9


agreed
for the hisogram one i got 2.5 width and 2.4 height

median 7.5
mean 8.115
Original post by CamoAssassin00
For the last question with bettys potatoes should be 6(0.25x0.25x0.5) since there were 6 arrangements of the possible potatoes


wouldn't it be 3 choose 2 potatoes, there are six ways to arrange the potatos but surely you have to remove the duplication of the 0.25 potatoes?
Reply 7
You man allow post your working out too. Especially for Q7/6/5 those IMO are kinda mad.
Original post by CamoAssassin00
For the last question with bettys potatoes should be 6(0.25x0.25x0.5) since there were 6 arrangements of the possible potatoes


A friend of mine suggested that as an answer.
Original post by ermalgfffv
for the hisogram one i got 2.5 width and 2.4 height

median 7.5
mean 8.115


got those 2 m8
Original post by Squiidsquid
wouldn't it be 3 choose 2 potatoes, there are six ways to arrange the potatos but surely you have to remove the duplication of the 0.25 potatoes?


Nope, one was below q1 one was above q3. Same probability, different potatoes. So it would be 3 permute 3.
what did everyone get for the regression line?
What was the probability of more than q3? And what was the LQ for last question
Original post by Squiidsquid
1a) a = 0.2
b = 0.6
c = 0.1
1b) F(7) = 0.9

histogram question:
2.5 width and 2.4 height
median 7.46
mean 8.115

2.
3.
4.
5. -1.89 degrees, something like t = 17.7 - 0.0126h
6.

7a) 0.1151
7b) 0.2215?
7c)123g?
7d) 3/32 ?


i got 8/3 for the height lmao
4. a. 0.1
b. 0.441
For question 3 which I believe was a normal distribution did ya'll get 0.44 something
Original post by CamoAssassin00
For the last question with bettys potatoes should be 6(0.25x0.25x0.5) since there were 6 arrangements of the possible potatoes

agreed
Did anyone get 5/21 for the probability of picking green, i did it via 2 methods and got the same answer. But i esentially did 5/84/ (probability of rg, rr, yr) as we know there are 47 red.
Original post by kkkfamyh132
What was the probability of more than q3? And what was the LQ for last question


I remember 7b was 0.25 plus 0.1151 so was equal to 0.3651 as was probability up to q3- the probability up to 92
Original post by yoyomynameis...
Did anyone get 5/21 for the probability of picking green, i did it via 2 methods and got the same answer. But i esentially did 5/84/ (probability of rg, rr, yr) as we know there are 47 red.


i thought there were 16 reds?

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