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# Ocr mei s2 watch

1. How'd it go?

I think the grade boundaries will be lower than usual due to the many explanation questions, and the two continuity correction questions.
2. did you get 0.3222 for one question
3. Did anyone approximate from binomial to normal for the out that was work out probability for 90 out of 100 (was 5 marks I think)
4. (Original post by Ivoryivory)
Did anyone approximate from binomial to normal for the out that was work out probability for 90 out of 100 (was 5 marks I think)
I did
5. That paper was so annoying like i messed up the chi squared because v was 6 instead of 4 and i messed up the approximating God knows how many more questions i messed up
6. (Original post by Ivoryivory)
Did anyone approximate from binomial to normal for the out that was work out probability for 90 out of 100 (was 5 marks I think)
did you get 0.3222 for that
7. i ****ed it up i got like reject h0 for all the hypothesis qs
8. What did people put for the question which asked why her friend couldn’t carry out the test after she’d found the PMCC as -0.138
9. Paper was ok, except for the wordy questions
For question 3, did people use binomial for two marker (10c10 and 10c9 added together)? And for the next 5 marker applied continuity correction, so it was 89.5 and used (mean=np=100*0.88, variance=now), got 0.322 as final answer?
I have rejected everything apart from the one chi squared I think
The PMCC was something like -0.18 or -0.8 something, cant remember but it was negative
There was a two tailed test for the mean so you have to split sl
10. (Original post by Luxyaaa)
did you get 0.3222 for one question
Yeeees, it was such a weird q, I spent ages on it
11. (Original post by Ivoryivory)
Did anyone approximate from binomial to normal for the out that was work out probability for 90 out of 100 (was 5 marks I think)
Yes
And applied continuity correction, got 0.3222
12. And i feel like i wrote the wrong conclusions
13. (Original post by Zgogol18)
Yes
And applied continuity correction, got 0.3222
yh i got that
14. 0.6031 or something like that for one q?
15. (Original post by DJBabooon)
0.6031 or something like that for one q?
yeah
17. (Original post by DJBabooon)
I said that the hypotheses need to be decided before the data is collected and shouldn’t be based on it and therefore the test would be unreliable as she already has the PMCC
18. 1(i)PMCC=-0.1842
ii insufficient evidence to reject
iii. Data must be drawn from population with bivariate normal distribution, it was roughly elliptical shape so seemed reliable
iv. Didn’t really know what to say, figure was for a whole population not from a sample?
v. Correlation doesn’t imply causation, might have been a third variable present that caused correlation

2i uniform, independent random rate of occurrence
ii. Variance=8.4
iii. 0.6013 I think this was p(x &amp;gt;=8) used tables
iv. 0.6502 p between two values I think

3. The two marker, 0.6573, using binomial
The five marker 0.3222

The mean test for two tailed, reject H0
The chi test first time didn’t have enough evidence to reject H0 for the second test rejected it I think
The standard deviation where the mean was constant was something close the the as that was given in the question, 0. Something

The rest I can’t really remember
19. First Pmcc test was two tailed as well
Didn’t need to split sl, just looked as two tailed Colloumn in the table
20. How did you define PMCC
I didn’t know how to define it, just said p(rho)- population PMCC for age and height

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