Kaytra
Badges: 2
Rep:
?
#1
Report Thread starter 1 year ago
#1
Well. F*ck.
0
reply
tedtheshred
Badges: 8
Rep:
?
#2
Report 1 year ago
#2
(Original post by Kaytra)
Well. F*ck.
What q's did you attempt?
0
reply
Kaytra
Badges: 2
Rep:
?
#3
Report Thread starter 1 year ago
#3
(Original post by tedtheshred)
What q's did you attempt?
1, 2 were ok, tried 4 and realised it was going to be disgusting so went for 3 and didn’t read that k was 3 and didn’t know how I was going to do the integral. Ended up only answering 1 and 2 fully 😰
0
reply
xiaochen
Badges: 13
Rep:
?
#4
Report 1 year ago
#4
I did questions 1 2 3 and 4 lol
finished all with about 3 mins to spare
question 4 was pretty horrible - solution for x had awkward coefficients and probably got the value for time wrong.
But betting on questions 1 2 and 3
1
reply
Tsr74
Badges: 2
Rep:
?
#5
Report 1 year ago
#5
What did you get for the time, I think I got 1.39 something but not too sure
0
reply
Kaytra
Badges: 2
Rep:
?
#6
Report Thread starter 1 year ago
#6
(Original post by Tsr74)
What did you get for the time, I think I got 1.39 something but not too sure
I think that's what I got too
0
reply
xiaochen
Badges: 13
Rep:
?
#7
Report 1 year ago
#7
Lol I definitely got that wrong. I kind of gave up a bit after getting the general solution for x.
Oh well I hope 1 2 and 3 went well for me
0
reply
W00113
Badges: 1
Rep:
?
#8
Report 1 year ago
#8
What was y when x is 1.8 for eulers in questions 3??
0
reply
xiaochen
Badges: 13
Rep:
?
#9
Report 1 year ago
#9
For the two solution curves in question 3 did any one get a parabolic shaped curve through (0,1) and a cubic shaped curve through (1,0)
And also the Euler method question 0.099 something?
And for some other question the exact value of y to be -1/16 pi^3 + 1/16 pi^2 or something similar (can’t remember my signs exactly)
0
reply
xiaochen
Badges: 13
Rep:
?
#10
Report 1 year ago
#10
(Original post by W00113)
What was y when x is 1.8 for eulers in questions 3??
I thought it was x=0.8

Well I got like 0.099... something
0
reply
W00113
Badges: 1
Rep:
?
#11
Report 1 year ago
#11
(Original post by xiaochen)
For the two solution curves in question 3 did any one get a parabolic shaped curve through (0,1) and a cubic shaped curve through (1,0)
And also the Euler method question 0.099 something?
And for some other question the exact value of y to be -1/16 pi^3 + 1/16 pi^2 or something similar (can’t remember my signs exactly)
yes i got 0.099 and the 1/16pi^3 + 1/16pi^2
0
reply
xiaochen
Badges: 13
Rep:
?
#12
Report 1 year ago
#12
(Original post by W00113)
yes i got 0.099 and the 1/16pi^3 + 1/16pi^2
Yayyy
0
reply
TauBilly
Badges: 11
Rep:
?
#13
Report 1 year ago
#13
(Original post by Tsr74)
What did you get for the time, I think I got 1.39 something but not too sure
The time for y to be 0 in Q4? Im pretty certain that was 0.0429? It was very easy to use the wrong solution to cos(...) = 1/2
0
reply
BD9
Badges: 0
Rep:
?
#14
Report 1 year ago
#14
(Original post by xiaochen)
For the two solution curves in question 3 did any one get a parabolic shaped curve through (0,1) and a cubic shaped curve through (1,0)
And also the Euler method question 0.099 something?
And for some other question the exact value of y to be -1/16 pi^3 + 1/16 pi^2 or something similar (can’t remember my signs exactly)
I thought one of coefficients was 1/64 or something
0
reply
xiaochen
Badges: 13
Rep:
?
#15
Report 1 year ago
#15
(Original post by TauBilly)
The time for y to be 0 in Q4? Im pretty certain that was 0.0429? It was very easy to use the wrong solution to cos(...) = 1/2
I got that I think??

I had to use rcos(theta+alpha) form to convert though...

Because I got y=e^4x (10cos3x +24sin3x -13)
0
reply
TauBilly
Badges: 11
Rep:
?
#16
Report 1 year ago
#16
(Original post by xiaochen)
I got that I think??

I had to use rcos(theta+alpha) form to convert though...

Because I got y=e^4x (10cos3x +24sin3x -13)
Yes you're right
0
reply
xiaochen
Badges: 13
Rep:
?
#17
Report 1 year ago
#17
(Original post by xiaochen)
I got that I think??

I had to use rcos(theta+alpha) form to convert though...

Because I got y=e^4x (10cos3x +24sin3x -13)
Lol wait I used the wrong value lmao and I noticed in the exam it was wrong but I did 4 questions so I had no time to correct - I remember now haha.

Oh well!
0
reply
xiaochen
Badges: 13
Rep:
?
#18
Report 1 year ago
#18
Name:  3EA48D19-C98F-4BD8-939B-FFB8D94D9403.jpeg
Views: 36
Size:  82.5 KB

TauBilly is right!! If PS for y is right.

Oh well if people used wrong cos solution we’ll probs only lose like 2 marks as it was 4 marks total
0
reply
tedtheshred
Badges: 8
Rep:
?
#19
Report 1 year ago
#19
(Original post by Kaytra)
1, 2 were ok, tried 4 and realised it was going to be disgusting so went for 3 and didn’t read that k was 3 and didn’t know how I was going to do the integral. Ended up only answering 1 and 2 fully 😰
Did 1,2,4. no problems there. 100 ums boundary?
0
reply
Kaytra
Badges: 2
Rep:
?
#20
Report Thread starter 1 year ago
#20
(Original post by tedtheshred)
Did 1,2,4. no problems there. 100 ums boundary?
Low I'm hoping but by the sounds of people on here I'm not to sure that'll be the case
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • The University of Law
    Solicitor Series: Assessing Trainee Skills – LPC, GDL and MA Law - Exeter campus Postgraduate
    Thu, 27 Feb '20
  • University of East Anglia
    PGCE Open day Postgraduate
    Sat, 29 Feb '20
  • Edinburgh Napier University
    Postgraduate Drop-in Brunch Postgraduate
    Sat, 29 Feb '20

Do you get study leave?

Yes- I like it (285)
60.51%
Yes- I don't like it (22)
4.67%
No- I want it (129)
27.39%
No- I don't want it (35)
7.43%

Watched Threads

View All