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# Mei c3 2018 watch

1. Expecting something nice after the M1? 19/06/2018
2. (Original post by Ryan Right)
Expecting something nice after the M1? 19/06/2018
true
3. (Original post by Ryan Right)
Expecting something nice after the M1? 19/06/2018
This belongs in the Maths Exams subforum, in order to avoid clogging up the main forum. Notnek request move?
4. C3 is a generally well comprehended module, so even if the paper isn't too nice, I'd expect high grade boundaries.
The last few C3 papers have been quite nice which is not a normal thing for MEI, so I wouldn't be surprised if this paper was quite challenging.

After that horrid excuse of an M1 paper though, I do feel as though MEI owe us
Regardless, good luck to everyone. All the best, and I'm sure you'll smash it!
5. what time is the exam again, I know its in the afternoon but forgot when :s

(Nvm just checked its at 13:00)
6. how did people find that
7. Relatively easy except for stupidly doing 2ln(x-2) by parts in 9(iv) smdh.
8. Pretty good. Wait I got 0.05 for the half life question for K, did I make a stupid mistake?
9. (Original post by lowkeybuthighkey)
Relatively easy except for stupidly doing 2ln(x-2) by parts in 9(iv) smdh.
i did it by parts too, what was the other way of doing it?
10. (Original post by Rowanhuggins123)
Pretty good. Wait I got 0.05 for the half life question for K, did I make a stupid mistake?
Yes because it asked for 2 sig fig
11. this is what i got, the rest were like show that..
• 1)(i) -3x/4y (ii)-6
• 2) (i) odd

(ii) periodic (pi/2)
(iii) even
• 3) (i)0%

(ii)k=0.048
• 4) (0.55, 0.514)
• 5) (ii) -1/3
• 6) (i) 5pi/6

(ii) sin(0.5(x-pi/2))
• 7) n^3-3n^2+2n. Prove it is divisible by 6 for all positive integers n. I factorized, they were 3 consecutive integers, so at least one divisible by 2 and one divisible by 3, thus it is divisible by 6
• 8) (i) equation of the tangent: x-4y-3=0

(iii) 23/8-4ln2
• 9) (ii) find P and Q. P(3,0) Q(4, ln4)

(iv) 4ln2-1
12. Yeah thought so ahah
13. (Original post by 2long)
this is what i got, the rest were like show that..
• 1)(i) -3x/4y (ii)-6
• 2) (i) odd

(ii) periodic (pi/2)
(iii) even
• 3) (i)0%

(ii)k=0.048
• 4) (0.55, 0.514)
• 5) (ii) -1/3
• 6) (i) 5pi/6

(ii) sin(0.5(x-pi/2))
• 7) n^3-3n^2+2n. Prove it is divisible by 6 for all positive integers n. I factorized, they were 3 consecutive integers, so at least one divisible by 2 and one divisible by 3, thus it is divisible by 6
• 8) (i) equation of the tangent: x-4y-3=0

(iii) 23/8-4ln2
• 9) (ii) find P and Q. P(3,0) Q(4, ln4)

(iv) 4ln2-1
I think I got all the same apart from 25% of substance left after 28.8 years
14. (Original post by 2long)
this is what i got, the rest were like show that..
• 1)(i) -3x/4y (ii)-6
• 2) (i) odd

(ii) periodic (pi/2)
(iii) even
• 3) (i)0%

(ii)k=0.048
• 4) (0.55, 0.514)
• 5) (ii) -1/3
• 6) (i) 5pi/6

(ii) sin(0.5(x-pi/2))
• 7) n^3-3n^2+2n. Prove it is divisible by 6 for all positive integers n. I factorized, they were 3 consecutive integers, so at least one divisible by 2 and one divisible by 3, thus it is divisible by 6
• 8) (i) equation of the tangent: x-4y-3=0

(iii) 23/8-4ln2
• 9) (ii) find P and Q. P(3,0) Q(4, ln4)

(iv) 4ln2-1
Yes although I think the period was pi
16. (Original post by 2long)
this is what i got, the rest were like show that..
• 1)(i) -3x/4y (ii)-6
• 2) (i) odd

(ii) periodic (pi/2)
(iii) even
• 3) (i)0%

(ii)k=0.048
• 4) (0.55, 0.514)
• 5) (ii) -1/3
• 6) (i) 5pi/6

(ii) sin(0.5(x-pi/2))
• 7) n^3-3n^2+2n. Prove it is divisible by 6 for all positive integers n. I factorized, they were 3 consecutive integers, so at least one divisible by 2 and one divisible by 3, thus it is divisible by 6
• 8) (i) equation of the tangent: x-4y-3=0

(iii) 23/8-4ln2
• 9) (ii) find P and Q. P(3,0) Q(4, ln4)

(iv) 4ln2-1
I got 8ln2 - 2 for the last part of last question... Can someone confirm this?
17. (Original post by uniftw)
I think I got all the same apart from 25% of substance left after 28.8 years
Your answer makes much more sense it was 1 mark so I kinda just guessed it lol
18. (Original post by a.b.a)
I got 8ln2 - 2 for the last part of last question... Can someone confirm this?
its 4ln2 -1
19. (Original post by 2long)
this is what i got, the rest were like show that..
• 1)(i) -3x/4y (ii)-6
• 2) (i) odd

(ii) periodic (pi/2)
(iii) even
• 3) (i)0.25%

(ii)k=0.048
• 4) (0.55, 0.514)
• 5) (ii) -1/3
• 6) (i) 5pi/6

(ii) sin(0.5(x-pi/2))
• 7) n^3-3n^2+2n. Prove it is divisible by 6 for all positive integers n. I factorized, they were 3 consecutive integers, so at least one divisible by 2 and one divisible by 3, thus it is divisible by 6
• 8) (i) equation of the tangent: x-4y-3=0

(iii) 23/8-4ln2
• 9) (ii) find P and Q. P(3,0) Q(4, ln4)

(iv) 4ln2-1

period is pi not pi over 2
20. The final answer for the last question I got 4ln2-1? The one where you had to write it in the form mln2-n

I got 25% for the half like one- but why the hell was there like half a page of answer space for that one mark? 😂

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