If you have integrated f(x) to F(x) is your new function the cumulative function? I.e. if in 2 parts, the 2nd part will also include the area under the curve for the first part? Hope that makes sense
edit: struggling to say exactly what I mean,
say if F(x) was defined in 2 parts, say one between 1<x<3 and one 4<x<7
If you wanted to find the probability that X is less than 6  would you only do F(6) in the 2nd function, or would you also do F(6) for the first function and add them?

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 18062018 21:09
Last edited by jazz_xox_; 18062018 at 21:12. 
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 18062018 21:26
I want to say that each 'section' of the function is only for that specific area under the curve, but then wouldn't that go against the idea of it being a cumulative function? Think I'm confusing myself here

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 18062018 21:30
Yes add them if it is less than 6. I'd explain better if it were a question. Don't forget Yates correction tomorrkw

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 18062018 21:33
(Original post by TheYearNiner)
Yes add them if it is less than 6. I'd explain better if it were a question. Don't forget Yates correction tomorrkw
Usually the questions makes it clear what they're after (e.g. to add on the first section of the area under the curve to give the whole cumulative function) and I've not had trouble with it before but I'm really confusing myself now!
And thank you, I won't forget!! Are you doing the exam too? 
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 18062018 21:35
(Original post by jazz_xox_)
If you have integrated f(x) to F(x) is your new function the cumulative function? I.e. if in 2 parts, the 2nd part will also include the area under the curve for the first part? Hope that makes sense
edit: struggling to say exactly what I mean,
say if F(x) was defined in 2 parts, say one between 1<x<3 and one 4<x<7
If you wanted to find the probability that X is less than 6  would you only do F(6) in the 2nd function, or would you also do F(6) for the first function and add them? 
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 18062018 21:36
(Original post by jazz_xox_)
Thank you, that's what I thought but then my friend was questioning me and I couldn't explain why.. so even though it's the 'cumulative' function, it doesn't necessarily include everything from 0, just in that section?
Usually the questions makes it clear what they're after (e.g. to add on the first section of the area under the curve to give the whole cumulative function) and I've not had trouble with it before but I'm really confusing myself now!
And thank you, I won't forget!! Are you doing the exam too? 
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 18062018 21:37
(Original post by Prasiortle)
If f(x) is the probability density function, then F(x) is the cumulative distribution function. However, if f(x) is defined piecewise, then you will need to add the areas to get the total (cumulative area), so to find P(X <= k) where k is less than 3, you would just do F(k) in the 1st function; to find P(X <= k) where k is more than 3, you would have to do F(3) in the 1st function to get that total area, then F(k) in the 2nd function to get that area, and then add the two areas.
When you've written F(x) as multiple pieces, defined for difference x values, would you still call this the 'cumulative distribution function' or not? 
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 18062018 21:38
(Original post by TheYearNiner)
Yeah I'm doing the exam but make sure you double check with textbook because I might be wrong I can be clumsy 
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 18062018 21:42
(Original post by jazz_xox_)
Ahh that helps a lot thank you! So it's cumulative if it's just defined in one section, but if it's defined for multiple sections, you would have to combine them to find the overall cumulative function?
When you've written F(x) as multiple pieces, defined for difference x values, would you still call this the 'cumulative distribution function' or not?
Yes, if it's piecewise, you have to combine them. It's the same as how, e.g. if you're using a velocitytime graph that has one section between time 0 seconds and time 5 seconds, and another (different) section between time 5 seconds and time 10 seconds, and you want to find the value of t such that the displacement (i.e. area under the velocitytime graph) at time t seconds is 3 metres, and you know that this value of t is between 5 and 10, then you have to do the total area from time 0 seconds up to time 5 seconds, plus the area from time 5 seconds up to time t seconds, as this will give the total area under the graph from time 0 seconds up to time t seconds. 
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 18062018 21:43
I'm getting confused now haha. Can someone please put an example of this type up because I can't find an example of this type in the textbook?
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 18062018 21:44
(Original post by Prasiortle)
It's still called a cumulative distribution function.
Yes, if it's piecewise, you have to combine them. It's the same as how, e.g. if you're using a velocitytime graph that has one section between time 0 seconds and time 5 seconds, and another (different) section between time 5 seconds and time 10 seconds, and you want to find the value of t such that the displacement (i.e. area under the velocitytime graph) at time t seconds is 3 metres, and you know that this value of t is between 5 and 10, then you have to do the total area from time 0 seconds up to time 5 seconds, plus the area from time 5 seconds up to time t seconds, as this will give the total area under the graph from time 0 seconds up to time t seconds. 
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 18062018 21:46
(Original post by Devvo666)
I'm getting confused now haha. Can someone please put an example of this type up because I can't find an example of this type in the textbook?
http://filestore.aqa.org.uk/subjects...BQPJUN14.PDF
7bi on this paper kind of helped me to understand it, in the way that you have to add on the first bit of the function 
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 18062018 21:50
(Original post by jazz_xox_)
Okay it's starting to make a lot more sense If you were to define the cumulative distribution function for the 2nd section of the function only, would you still add on the area from the first part of the curve then? 
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 18062018 22:01
(Original post by jazz_xox_)
If you have integrated f(x) to F(x) is your new function the cumulative function? I.e. if in 2 parts, the 2nd part will also include the area under the curve for the first part? Hope that makes sense
edit: struggling to say exactly what I mean,
say if F(x) was defined in 2 parts, say one between 1<x<3 and one 4<x<7
If you wanted to find the probability that X is less than 6  would you only do F(6) in the 2nd function, or would you also do F(6) for the first function and add them? 
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 18062018 22:14
I don't understand how you get the shape of the graph for this question or the 2 parts to b. Can anyone help?
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Prasiortle
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 19062018 00:12
(Original post by Devvo666)
I don't understand how you get the shape of the graph for this question or the 2 parts to b. Can anyone help?
Anyway, to sketch the graph, just notice that is a quartic with double roots, and thus stationary points, at and (double roots due to the brackets being squared).
For (b)(i): We have , so , which by linearity of expectation becomes , and now you just have to substitute in your value of from part (a)(iii).
Then for (b)(ii): we have , and this time we apply the rule that when and are constants, , which can itself be derived from linearity of expectation. Thus we get , and again we just have to substitute in our value of from part (a)(iv).Last edited by Prasiortle; 19062018 at 00:13. 
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 19062018 07:45
(Original post by Prasiortle)
The cumulative distribution function is defined piecewise: for the first section, it's just the integral from the start point up to x of the first section of the probability density function; for the second section, it's the integral over the entire domain (start point up to end point) of the first section of the probability density function, plus the integral from the second section's start point up to x of the probability density function.
So if you’ve just integrated the second part of the function (ignoring the first part) is that just the area under that section of the curve?? 
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 19062018 07:46
(Original post by Martha8)
F(x) by definition is the integral of f(x) from ve infinity up to x, so to find the probability that x < 6, you just need to do F(6) in the 2nd function; the height described by the first function (ie in this case the probability that x < 3) is accounted for as the '+c' when you integrate from f(x) > F(x) for the 2nd function. 
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 19062018 08:02
(Original post by jazz_xox_)
Ahh okay .. so you wouldn’t need to add on the first section of Fx at all? 
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 19062018 08:11
(Original post by Prasiortle)
You cannot get the cumulative distribution function as one thing, because you have to know which section of the graph your ending value falls into in order to work out the area. If your ending value falls in the first section, you will need to add the entire area of the first section to a certain area under the second section.
So my understanding now is, the whole collection of functions is the cumulative distribution function, and to find an area below a point in the section section, you also need to add on the area under the curve for the first section ? I don’t know how I’ve never noticed that this didn’t make sense to me before !
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