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# AQA GCSE Further Maths 2018 unofficial mark scheme paper 1 watch

1. What did you guys get? Let's make an unofficial mark scheme
2. For the 6 mark simultaneous equation

X was either 1/3 or -2
Y was either 6 or -1
3. (Original post by johnthebaptist27)
What did you guys get? Let's make an unofficial mark scheme
(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one
Solutions for simultaneous was (1/3, 6), (-2,-1) I think
K was 17
2x^2+16x+13 was 2(x-4)^2 -19
I think matrices was r1 c1 (4), R1 c2 (16), forgot R2 c1 but R2 c2 was 17
The first one I think was 3x^2 + x^3 I don't remember properly
-2 -7 was a and b respectively for the second one I think or it was for the coordinates of P when another line was parallel to the line tangent to the curve
(X+2)^2+(y-5)^2=25 given (-2,5)
48 one of them
Question with P and Q: x was 35
4. 20. I'm pretty sure that I got 4 root 3.
I got k as 17 for the quadratic expansion question.
5. (Original post by Jakazen)
(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one
Yeah same here
The first one was 3x^5 +x^3 (because it was (x^6)/2 +(x^4)/4) I think
And I'm pretty sure that R2 C1 was -8
6. For the line draw one I drew y = 2-x for answers of 3.6 and 0.6.
7. (Original post by Jakazen)
(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one
same here
8. (Original post by johnthebaptist27)
For the line draw one I drew y = 2-x for answers of 3.6 and 0.6.
How did you work that one out? I got really stuck and put some random working down in the hope I might get a method mark (unlikely lol)
9. (Original post by johnthebaptist27)
For the line draw one I drew y = 2-x for answers of 3.6 and 0.6.
Omg I was so unsure on that and wasn't really sure what I was doing. Do you think that was right?

I also got that btw
10. (Original post by johnthebaptist27)
For the line draw one I drew y = 2-x for answers of 3.6 and 0.6.
i got 3.4 and 0.6
11. (Original post by LottieLouLou)
How did you work that one out? I got really stuck and put some random working down in the hope I might get a method mark (unlikely lol)
Well you were given a graph of 3x-x^2 and asked to solve x^2-4x+2, so if you add the two together, you get x^2 - x^2 +3x-4x + 2 = 2-x. THen draw this line on the graph and circle where 3x-x^2 and 2-x intersect
12. (Original post by 13dsaivaines)
Omg I was so unsure on that and wasn't really sure what I was doing. Do you think that was right?

I also got that btw
Yh i am pretty sure because I checked in the exam and if you get the graph of x^2 -4x + 2 and complete the square, you get (x-2)^2 -2 = 0, hence x = 2+-sqrt(2), and i took the root of 2 to be 1.4 (remeber it as this), which gives 0.6 and 3.4
13. (Original post by Jakazen)
(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one
Solutions for simultaneous was (-1/3, -6), (2,1) I think
K was 17
2x^2+16x+13 was 2(x-4)^2 -19
I think matrices was r1 c1 (4), R1 c2 (16), forgot R2 c1 but R2 c2 was 17
The first one I think was 3x^2 + x^3
-2 -7 was a and b respectively for the second one I think or it was for the coordinates of P when another line was parallel to the line tangent to the curve
(X+2)^2+(y-5)^2=25 given (-2,5)
I think I got 3x^5+x^3 for the first one and for the simultaneous I got 1/3 and 6, & -1 and -2
14. (Original post by somebrick)
i got 3.4 and 0.6
yeah thats what I got i remembered incorrectly
15. (Original post by johnthebaptist27)
Yh i am pretty sure because I checked in the exam and if you get the graph of x^2 -4x + 2 and complete the square, you get (x-2)^2 -2 = 0, hence x = 2+-sqrt(2), and i took the root of 2 to be 1.4 (remeber it as this), which gives 0.6 and 3.4

Yeah I did that as well and solved it using the quadratic formula but thought the root of 2 was 1.8 lol
16. (Original post by Flyn_Higginson)
Yeah same here
What was the question for
Y = 3/5x +25
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17. • The question where you had to work out the coordinates of point P on the curve with its tangent parallel to a given equation of a line:
(-0.70, -10.12).
• Last question (trig/surds): 4√3 (in the form a√b)
• Sketch question: obviously I can't show a sketch here but the coordinates, Max (-3, 13) & Min (1, 2⅓) and you roughly crossed the y-axis at (0,4).
• K = 17
• I didn't do quite well in the circle theorem but ig the main important angle (imo) that I worked out was 2x for one of the angles in the cyclic quadrilateral. I knew you ultimately needed to show two corresponding or alternate angles were equal to prove that the two lines were parallel, but I couldn't work the values
• equation for circle (tick box q): (x+1)²+(y-6)² = 25. I'm not quite sure about the actual coordinates of the centre given to us but it defo was a '+' in the 1st bracket, a '-' in the 2nd then 25 (5² = 25).
18. (Original post by somebrick)
i got 3.4 and 0.6
same complete guess aha. apart from this i found everything else alright
19. (Original post by Jakazen)
(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one
Solutions for simultaneous was (-1/3, -6), (2,1) I think
K was 17
2x^2+16x+13 was 2(x-4)^2 -19
I think matrices was r1 c1 (4), R1 c2 (16), forgot R2 c1 but R2 c2 was 17
The first one I think was 3x^2 + x^3
-2 -7 was a and b respectively for the second one I think or it was for the coordinates of P when another line was parallel to the line tangent to the curve
(X+2)^2+(y-5)^2=25 given (-2,5)
48 one of them
yea i got these
20. What was the answer for x for the first circle theorem question with x + 75 and 2x?

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