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AQA Further Maths GCSE 2018 Unofficial Mark Scheme

I am not by any means saying these are the right answers, these are the ones I can remember I wrote down everyone else add your answers!
Lasts question 4root3
P is 28 greater than q: x= 20??
k (constant) = 17/18 can’t remember
Reply 1
Avatar for matt750
matt750
2
yh 4root 3 for the last question
Reply 2
Avatar for matt750
matt750
2
I think I got (x-3)(x-5)(x-5)for one
Reply 3
Avatar for sescg
sescg
6
the constant was 17 pretty sure
Original post by Lol123123123
I am not by any means saying these are the right answers, these are the ones I can remember I wrote down everyone else add your answers!
Lasts question 4root3
P is 28 greater than q: x= 20??
k (constant) = 17/18 can’t remember

I got 8root3 for the last question
k = 17
Reply 5
Avatar for matt750
matt750
2
yh I got that
Reply 6
Avatar for Pabzeee
Pabzeee
3
Please do correct me on any wrong answers :smile:

1) 3x^5 + x^3
2) a= -3 b= 10. (I think this ones wrong)
3) 4,16
-8 17
4) 35
5) 17
6) (x+1)^2 + (y-2)^2 = 25
7) 25
8) -6+ 7 root 5 (not sure)
9) plus or minus the square root of 9/4
---next few question numbers might not be in the right order)
10) x= -1 / 3-4y. (not sure)
11) -2, -7 (not sure)
12) y = 3/5 x +25
13) x= -2 or 1/3
y= -1 or 6
14) 48
15) ----
16) ----
17) u put 2 into the equation and make it equal to 0
17b) (x-2)(x-5)(x-5)
18) think this was the proof question : alternate segment theorem, alternate angles etc
19) 2(x-4)^2 -19 (not sure)
20) 4 root 3
Reply 7
Avatar for JasXx
JasXx
3
Is it okay if I factored out x^3 for the first one so x^3(3x^2+1)?
Original post by Pabzeee
Please do correct me on any wrong answers :smile:

1) 3x^5 + x^3
2) a= -3 b= 10. (I think this ones wrong)
3) 4,16
-8 17
4) 35
5) 17
6) (x+1)^2 + (y-2)^2 = 25
7) 25
8) -6+ 7 root 5 (not sure)
9) plus or minus the square root of 9/4
---next few question numbers might not be in the right order)
10) x= -1 / 3-4y. (not sure)
11) -2, -7 (not sure)
12) y = 3/5 x +25
13) x= -2 or 1/3
y= -1 or 6
14) 48
15) ----
16) ----
17) u put 2 into the equation and make it equal to 0
17b) (x-2)(x-5)(x-5)
18) think this was the proof question : alternate segment theorem, alternate angles etc
19) 2(x-4)^2 -19 (not sure)
20) 4 root 3


Yh I got -3 and 10 for question 2.
For question 8 I got 4 + 5 root 5.
For question 9, I simplified the + or - root 9/4 to + or - 3/2.
For question 17b I got (x+5)^2(x-2).
For question 19, I got the same: 2(x-4)^2 -19
Original post by JasXx
Is it okay if I factored out x^3 for the first one so x^3(3x^2+1)?


Yh probably, because normally they have “Oe” on the side of the markscheme which stands for “or otherwise” which means they should accept the same answer even if it is in different forms. E.g. 9/4 and 3/2
Reply 10
Avatar for JasXx
JasXx
3
That’s a relief, thanks
Reply 11
Avatar for Pabzeee
Pabzeee
3
Original post by samsam78910
Yh I got -3 and 10 for question 2.
For question 8 I got 4 + 5 root 5.
For question 9, I simplified the + or - root 9/4 to + or - 3/2.
For question 17b I got (x+5)^2(x-2).
For question 19, I got the same: 2(x-4)^2 -19


for 17b) I think its fine if you do either (x+5)(x+5)(x-2) or (x+5)^2 (x-2)
For 9) do you think I'd still get the marks without cancelling down.
what did any of you get for question 15???
I got 3.15 and 1.3 on the graph
Reply 13
Avatar for Zaman27
Zaman27
9
Original post by Mylifeismaths
what did any of you get for question 15???
I got 3.15 and 1.3 on the graph


0.6 and 3.4 I think
Reply 14
Avatar for Zaman27
Zaman27
9
For the simultaneous question I wrote the answer in pairs e.g. when x= whatever value it was, y=.....
Then underneath it I wrote the same thing but with the other values of x and y as a pair.
Would I get the marks for writing my answer like that?
Hello, could someone please upload the questions!

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