Ok long mechanics question...
Two identical beads A and E, each of mass m are threaded on a rough straight horizontal wire. The beads are joined by a light inextensible string of length 4a. Particles B, C, D, each of mass 2m, are attached to the string so that AB = BC = CD = DE = a. The system hangs freely under gravity in a vertical plane. The coefficient of friction between each bead and the wire is 1/4. Prove that, for the system in equilibrium in a symmetrical shape, the greatest possible value of the distance AE is:
2a(1/root10 + 1/root2)
Good luck