# Statistics Question Urgent Help Watch

Doing an S2 question and I don't get this

Biased 4 sided spinner can only land on 1,2,3,4

Random Variable X is the number that the spinner lands on after a single spin

P(X=q) = P(X=q+2) for q=1.2

Given P(X=2) = 0.35

(a) Find the complete probability distribution of q

(b) spinner spinned 50 times

find probability more than half land on number 4

The random variable

12

Y= ----

X

Find P (Y-X<=4)

Find P( Y - X less or equal to 4)

Biased 4 sided spinner can only land on 1,2,3,4

Random Variable X is the number that the spinner lands on after a single spin

P(X=q) = P(X=q+2) for q=1.2

Given P(X=2) = 0.35

(a) Find the complete probability distribution of q

(b) spinner spinned 50 times

find probability more than half land on number 4

The random variable

12

Y= ----

X

Find P (Y-X<=4)

Find P( Y - X less or equal to 4)

0

reply

Report

#5

(Original post by

bump

**Pakora99**)bump

Please link the original question.

0

reply

(Original post by

Insufficient information to resolve the problem - unless it's to be left in terms of a parameter.

Please link the original question.

**ghostwalker**)Insufficient information to resolve the problem - unless it's to be left in terms of a parameter.

Please link the original question.

updated it at the top as well

0

reply

Report

#7

(Original post by

sorry bout that forgot to add this bit Given P(X=2) = 0.35

updated it at the top as well

**Pakora99**)sorry bout that forgot to add this bit Given P(X=2) = 0.35

updated it at the top as well

P(X=2) = P(X=4) = 0.35

P(X=1) = P(X=3) = ?

And use the fact that the total probability must be 1, to work out the unknown value.

0

reply

(Original post by

From the question, then:

P(X=2) = P(X=4) = 0.35

P(X=1) = P(X=3) = ?

And use the fact that the total probability must be 1, to work out the unknown value.

**ghostwalker**)From the question, then:

P(X=2) = P(X=4) = 0.35

P(X=1) = P(X=3) = ?

And use the fact that the total probability must be 1, to work out the unknown value.

0

reply

**ghostwalker**)

From the question, then:

P(X=2) = P(X=4) = 0.35

P(X=1) = P(X=3) = ?

And use the fact that the total probability must be 1, to work out the unknown value.

P(X=3) =0.15

0

reply

Report

#10

(Original post by

P(X=2) = P(X=4) = 0.35 how do you know 2 and 4 are related

**Pakora99**)P(X=2) = P(X=4) = 0.35 how do you know 2 and 4 are related

"P(X=q) = P(X=q+2) for q=1.2"

Setting q=2

P(X=2) = P(X=4)

1

reply

(Original post by

Question tells you.

"P(X=q) = P(X=q+2) for q=1.2"

Setting q=2

P(X=2) = P(X=4)

**ghostwalker**)Question tells you.

"P(X=q) = P(X=q+2) for q=1.2"

Setting q=2

P(X=2) = P(X=4)

0

reply

1-P(X<25) = P(X>25)

1-P(X{less or equal} 25) = P(X>25)

let x be 0.35

0.989956 for P(X<25)

1-0.989956=0.01

not too sure on this bit if I've done It right

0

reply

Report

#14

(Original post by

Looks like binomial distribution so I've done

1-P(X<25) = P(X>25)

1-P(X{less or equal} 25) = P(X>25)

**Pakora99**)Looks like binomial distribution so I've done

1-P(X<25) = P(X>25)

1-P(X{less or equal} 25) = P(X>25)

let x be 0.35

Probability of success on a single spin.

0.989956 for P(X<25)

1-0.989956=0.01

not too sure on this bit if I've done It right

1-0.989956=0.01

not too sure on this bit if I've done It right

0

reply

FindP(Yâˆ’Xâ‰¤4)

I was thinking about finding in the 50 spins where X is less or equal to 4

But how would I do the Y bit?

Sorry about no latex I can't figure out how to use it

0

reply

Report

#16

(Original post by

y=12/X

FindP(Yâˆ’Xâ‰¤4)

I was thinking about finding in the 50 spins where X is less or equal to 4

But how would I do the Y bit?

Sorry about no latex I can't figure out how to use it

**Pakora99**)y=12/X

FindP(Yâˆ’Xâ‰¤4)

I was thinking about finding in the 50 spins where X is less or equal to 4

But how would I do the Y bit?

Sorry about no latex I can't figure out how to use it

You're only dealing with 1 spin, with r.v. X

So, you just need to check when . There are only 4 values, with their corresponding probabilities.

0

reply

(Original post by

The 50 spins don't come into it, unless there's something you've not posted.

You're only dealing with 1 spin, with r.v. X

So, you just need to check when . There are only 4 values, with their corresponding probabilities.

**ghostwalker**)The 50 spins don't come into it, unless there's something you've not posted.

You're only dealing with 1 spin, with r.v. X

So, you just need to check when . There are only 4 values, with their corresponding probabilities.

all values less than it is 0.65 and including is equal to 1

cuz P(X=4) is 0.35 all values less is 0.65

0

reply

Report

#18

(Original post by

If P(X<=4) then

all values less than it is 0.65 and including is equal to 1

cuz P(X=4) is 0.35 all values less is 0.65

**Pakora99**)If P(X<=4) then

all values less than it is 0.65 and including is equal to 1

cuz P(X=4) is 0.35 all values less is 0.65

You're interested in P(12/X-X<= 4), not P(X<= 4)

You need to evaluate that function over the domain of X, i.e. 1,2,3,4. And check if that function is <=4.

0

reply

(Original post by

OK, I think I know what you mean, but so what!

You're interested in P(12/X-X<= 4), not P(X<= 4)

You need to evaluate that function over the domain of X, i.e. 1,2,3,4. And check if that function is <=4.

**ghostwalker**)OK, I think I know what you mean, but so what!

You're interested in P(12/X-X<= 4), not P(X<= 4)

You need to evaluate that function over the domain of X, i.e. 1,2,3,4. And check if that function is <=4.

0

reply

Report

#20

(Original post by

I don't know where to start

**Pakora99**)I don't know where to start

This is >4, so we don't include P(X=1) in the sum of the probability.

Etc.

0

reply

X

### Quick Reply

Back

to top

to top