Deducing Empirical Fomulae - Need Help (AS)

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amphibology
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Alright so because I'm bored and start Y12 in a couple of months, I decided to look ahead and work on some of the powerpoints and uh... I'm stuck?

I got the first 3 ones on here pretty easily, but I have no clue how to get that Amino Acid D is Threonine and AA E is alanine?? So um, could someone ppllleeaassee help, thanks!

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kurtwhite23
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It's just empirical formula calculations, like at GCSE:
(% or mass divide by RAM; then divide by smallest number)

For Amino Acid D:

C: (40.3/12)
H: (7.6/1)
N: (11.8/14)
O: (40.3/16)

Gives a C : H : N : O ratio of 3.3 : 7.6 : 0.8 : 2.5
- Divide by smallest number to get a close-to-integer ratio, and you get 4 : 9 : 1 : 3

So C4H9NO3 - this is theronine.

Same for E... in the end, you get a 3 : 7 : 1 : 2 ratio (to closest integer) - so C3H7NO2 - alanine.
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amphibology
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(Original post by kurtwhite23)
It's just empirical formula calculations, like at GCSE:
(% or mass divide by RAM; then divide by smallest number)

For Amino Acid D:

C: (40.3/12)
H: (7.6/1)
N: (11.8/14)
O: (40.3/16)

Gives a C : H : N : O ratio of 3.3 : 7.6 : 0.8 : 2.5
- Divide by smallest number to get a close-to-integer ratio, and you get 4 : 9 : 1 : 3

So C4H9NO3 - this is theronine.

Same for E... in the end, you get a 3 : 7 : 1 : 2 ratio (to closest integer) - so C3H7NO2 - alanine.
Ah right, thank u so so much! Yeah i was getting confused and doing all kinds of things like doing the 40.3%*12 and stuff
I guess I just forgot that the formula is % too, not just mass, oops anyway, thanks again
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