Hi everyone,
I'm having real trouble figuring out how to do part ii).
The track for an overhead railway lies along DEF, where D and E have position vectors d = 130i - 40j + 20k and e = 90i - 20j + 15k, and F is a point on the ski-slope.
i) Find the equation of the straight line DE.
This equals r = (130i - 40j + 20k) + λ(8i - 4j + k), as far I can see.
But then part ii)...
ii) Find the position vector of the point F.
I'm at a loss, any help is much appreciated!