swastikwagle
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  1. Burette reading in ml

    Initial: (1)-0 (2)-0 (3)-0

    Final: (1)-11.5 (2)-11.4 (3)-11.4

    Difference: (1)-11.5 (2)11.4 (3)-11.4



    Pilot 11-12



    Concordant : 11.4



    Normality of Hcl

    Hcl v/s NaOH

    N₁V₁ = N₂V₂

    N₁.10 = 0.05 (11.4)

    N₁= 5.7



    Morality of HCL

    M = N/a

    M= 5.7/11.4

    M=0.5

    When i showed this to teacher, she said it is wrong.Why? Pleae explain
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username4178876
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(Original post by swastikwagle)
  1. Burette reading in ml

    Initial: (1)-0 (2)-0 (3)-0

    Final: (1)-11.5 (2)-11.4 (3)-11.4

    Difference: (1)-11.5 (2)11.4 (3)-11.4



    Pilot 11-12



    Concordant : 11.4



    Normality of Hcl

    Hcl v/s NaOH

    N₁V₁ = N₂V₂

    N₁.10 = 0.05 (11.4)

    N₁= 5.7



    Morality of HCL

    M = N/a

    M= 5.7/11.4

    M=0.5

    When i showed this to teacher, she said it is wrong.Why? Pleae explain
She said it's wrong but didn't explain why? Isn't that supposed to be her job?
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Sinnoh
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I think you messed up your calculation. (0.05×11.4)÷10 isn't 5.7
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