yusyus
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#1
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I have this integral and the answer is not the same as on the calculator but im not sure if its right or wrong.
∫1/cos^2(x)(tan^3(x)-tan(x)) . I simplified it down to ∫sin(2x)/cos^2((2x)-1 . I then substituted cos(2x) and the integral came out eventually as (ln(-cot^2(x)))/4
I'm not sure that's right or how to really check it?
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ghostwalker
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#2
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(Original post by yusyus)
I have this integral and the answer is not the same as on the calculator but im not sure if its right or wrong.
∫1/cos^2(x)(tan^3(x)-tan(x)) . I simplified it down to ∫sin(2x)/cos^2((2x)-1 . I then substituted cos(2x) and the integral came out eventually as (ln(-cot^2(x)))/4
I'm not sure that's right or how to really check it?
Given that your answer takes the ln of a negative number, it's not going to be correct. Check for mistakes, and/or post your full working.
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yusyus
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(Original post by ghostwalker)
Given that your answer takes the ln of a negative number, it's not going to be correct. Check for mistakes, and/or post your full working.
Hi, this is my working I did make a mistake originally but I'm not sure how to check my answer now
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yusyus
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(Original post by TeeEm)
Try the substitution u=tanx from the start
ahh, that does seem like a much easier method now, I just want to see if my original method is right though. Thanks!
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ghostwalker
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(Original post by yusyus)
I just want to see if my original method is right though. Thanks!
Your log manipulation at the end has a rather basic error.

You seem to have done essentially, ln(a-b) = ln(a) - ln(b).

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yusyus
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(Original post by ghostwalker)
Your log manipulation at the end has a rather basic error.

You seem to have done essentially, ln(a-b) = ln(a) - ln(b).

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I guess I can blame that on my lack of practice - thanks. Is it right before that point though?
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ghostwalker
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(Original post by yusyus)
I guess I can blame that on my lack of practice - thanks. Is it right before that point though?
Didn't spot any errors.

As a check, you can differentiate to see if you get back to your original function. Rather tedious in this case; I'd recommend using Wolfram Alpha (just google it). It takes a little while to pick up the syntax/vocab, but worth the effort. Easiest to check out their examples when starting out.
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