Gcse maths help

A rectangular container is 12 cm long 11cm wide and 10cm high. The container is filled with water to a depth of 8cm. A metal sphere of radius 3.5cm is placed in the water. It sinks to the bottom.

Calculate the rise in the water level

What i have done

Volume of sphere = 4/3*pi*3.5(to the power of 3)
= 179.59438... cm(cubed)
Volume of water in container = pi*3.5(squared) *8
=307.876......cm(cubed)

307.876.../179.594.... = 1.714.... cm
1.71(3sf) = rise in water level

the rise will just be the volume of the sphere right?

that’s what I’d think right, like that’s how I learnt about it in physics

that’s what I’d think right, like that’s how I learnt about it in physics

I know I'm a couple of years late, but this is how you do it:
Work out the volume of water first:
1. base x height x width --------------> 8 x 12 x 11 = 1056 cm^3
Then find the volume of the sphere:
2. 4/3 x pie x r^3 = volume of sphere --------------> 4/3 x pie x 3.5^3 = 179.59438 cm^3 tip: do not round at all so answer is accurate as possible
Then add these two values together:
179.59438 + 1056 = 1235.59438 = sphere + water
3. Create an algebraic expression to work out the new height of the water
Y x (12 x 11) = 1235.59438
Y= 1235.59438 / 12 x 11
Y= 9.8364 cm ---------> this is the new height, we still have to calculate the rise, so the difference between the new and original height of water
4. 10- 9.8364 = 0.164 cm to 3 s.f
Where ever you are right now, hope this helps!