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25.0cm^3 of 0.063M solution containing a base M(OH)n requires 23.60 cm^3 of 0.10M sulphuric acid for complete reaction. calculate the value of n?
Reply 1
Moved to Chemistry
Reply 2
You can use the equation ncv=ncv one side is strong acid the other is strong base. n means number of OH/H v means volume in cm^3 c means concentration.
n×25×0.063=2(number of hydrogen in sulphuric acid)× 23.6×0.1
Then I guess you can work out the rest sorry I don't have a calculator at hand i would have typed it. Btw I'm not sure this way is the right way for your question but I hope it helps
(edited 5 years ago)
Reply 3
1.575n=4.72
4.72/1.575 = 2.99...
So n=3
Reply 4
Original post by Chrispa
1.575n=4.72
4.72/1.575 = 2.99...
So n=3

The answer is n=2
Original post by Ohana Tan
25.0cm^3 of 0.063M solution containing a base M(OH)n requires 23.60 cm^3 of 0.10M sulphuric acid for complete reaction. calculate the value of n?


One mol of hydrogen ions reacts with one mole of hydroxide ions.

So calculate the moles of hydrogen ions provided by the sulfuric acid = 2 x 0.1 x 0.0236 = 0.00472 mol

Moles of base = 0.025 x 0.063 = 0.001575 mol

So this number of moles of base must provide the same moles of hydroxide ions as hydrogen ions

Hence n = 0.00472/0.001575 = 3
Reply 6
Original post by Ohana Tan
The answer is n=2

Oh sorry then I've tried working it out again and I think maybe you have to take into account the fact that when both are together the volume changes. But I still can't get n=2. I hope your find the answer sorry
Reply 7
Original post by Chrispa
Oh sorry then I've tried working it out again and I think maybe you have to take into account the fact that when both are together the volume changes. But I still can't get n=2. I hope your find the answer sorry

It's OK , thank you very much

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