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#2
You can use Avogadro's Number (6.02x10^23) and the Mass Moles and Mr Triangle to work this problem out
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#3
(Original post by Ohana Tan)
What is the number of atoms in 12.8g of methane, CH4 solid ?
What is the number of atoms in 12.8g of methane, CH4 solid ?
I think it'll be:
• moles = mass in grams ÷ molar mass (Mr)
• no. of atoms = moles × Avogadro Constant
= 12.8g ÷ ((12) plus (1×4))
= (12.8g ÷ 16)
= 0.8 mol × (6.02 × 10^23) - Avogadro Constant
= 4.816 × 10^23 (so approx. 4.82 × 10^23)
*** sorry if my working / answer is incorrect; just wanted to help out!
***
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(Original post by reyxhh)
number of atoms could be referring to "moles" - hence the Avogadro Constant in this question since you've got the mass in grams and you'll need the molar mass of CH4
I think it'll be:
• moles = mass in grams ÷ molar mass (Mr)
• no. of atoms = moles × Avogadro Constant
= 12.8g ÷ ((12) plus (1×4))
= (12.8g ÷ 16)
= 0.8 mol × (6.02 × 10^23) - Avogadro Constant
= 4.816 × 10^23 (so approx. 4.82 × 10^23)
*** sorry if my working / answer is incorrect; just wanted to help out!
***
number of atoms could be referring to "moles" - hence the Avogadro Constant in this question since you've got the mass in grams and you'll need the molar mass of CH4
I think it'll be:
• moles = mass in grams ÷ molar mass (Mr)
• no. of atoms = moles × Avogadro Constant
= 12.8g ÷ ((12) plus (1×4))
= (12.8g ÷ 16)
= 0.8 mol × (6.02 × 10^23) - Avogadro Constant
= 4.816 × 10^23 (so approx. 4.82 × 10^23)
*** sorry if my working / answer is incorrect; just wanted to help out!
***
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#5
(Original post by Ohana Tan)
But it is asking number of atoms , no the molecules
But it is asking number of atoms , no the molecules
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