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How to answer this math question

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Original post by London090
I've just finished my calculations but it looks like @missradioactive has beat me to it! She replied to your question with the calculations in the other thread :smile:

But I can still give you the walk through if you want.


yh I didn’t get her working out. I’d like it if ppl made it more simpler lol
Original post by Rainfall
yay I got it thanks! that’s true so will u help me with this question pls?

I tried working it out but


8power6/4power3*2power5 = 2power18 / 2power6 * 2power5 = 2power(18-6+5) = 2power17 = 131072
Original post by the bear
i would try to write it in "text speak" but i am not fluent :dontknow:


I don’t need to type it anyway, I can just post a picture of my working out on my notebook
Original post by Rainfall
yh I didn’t get her working out. I’d like it if ppl made it more simpler lol


😂😂 I'm about to go to bed, I will give you a simpler explanation tomorrow :smile:

I live in China btw so it's like 9:30pm here...
Original post by London090
😂😂 I'm about to go to bed, I will give you a simpler explanation tomorrow :smile:

I live in China btw so it's like 9:30pm here...


Aw ok goodnight.

Oh are you Chinese?

Thanks btw but I’m trying to get all of this done today so I can move on (I have no time) x
Original post by Rainfall
Aw ok goodnight.

Oh are you Chinese?

Thanks btw but I’m trying to get all of this done today so I can move on (I have no time) x


:smile: Nope I'm not Chinese I'm German Malaysian.

Good luck with the maths, please don't hesitate to PM me if you need help❤️
9^3 x 27^2

the answer wants to be a single power of 3, so we need to change 9 and 27 into a square of 3
so 9 = 3^2
and 27 = 3^3

since we have 9^3 in the question - we can now turn that into (3^2)^3 where 3^2 = 9
using indicy laws you get the ^2 and the ^3 and times them together to make 6, so we are left with 3^6
are you able to do the 27?
Original post by Rainfall
I didn’t understand a word you just said lol

32

Just testing to see if it actually works.
Original post by Gent2324
9^3 x 27^2

the answer wants to be a single power of 3, so we need to change 9 and 27 into a square of 3
so 9 = 3^2
and 27 = 3^3

since we have 9^3 in the question - we can now turn that into (3^2)^3 where 3^2 = 9
using indicy laws you get the ^2 and the ^3 and times them together to make 6, so we are left with 3^6
are you able to do the 27?


I’ve already done this question and answered it more simply

Its question 6 that I don’t get
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Original post by Rainfall
I’ve already done this question and answered it more simply

Its question 6 that I don’t get


it's just the same thing but with more terms
(edited 5 years ago)
Original post by yolkie
it's just the same thing but with more terms


Ok so where do I go from here ?

2 x 4 is 8
2 x2 is 4
2x1 is 2

That’s what I did with the first one , similar working out but now there’s a division involved ...
8^6 / (4^3 x 2^5)
since the answer wants it as a power of 2 we can turn 8 into a power of 2, which is 2^3 - making 8^6 into (2^3)^6
we can turn 4^3 into (2^2)^2 since 2^2 = 4
and we can leave 2^5 as it is
so we now have:

(2^3)^6 / (2^2)^2 x 2^5)

using indicy laws, (2^3)^6 because 2^18 because 6x3 = 18
(2^2)^2 = 2^4 because 2x2 = 4
now we have:

2^18 / (2^4 x 2^5 )

2^4 x 2^5 = 2^9 because you add the powers, since the 2 numbers are multiplied.

so now its 2^18 / 2^9 , since we are now dividing we take away the powers, so 18-9 = 9 , leaving us with 2^9
Original post by RichPiana
32

Just testing to see if it actually works.


:five:

:smug:
Original post by Rainfall
Ok so where do I go from here ?

2 x 4 is 8
2 x2 is 4
2x1 is 2

That’s what I did with the first one , similar working out but now there’s a division involved ...


23=8
22=4
so substituting these into the first expression

(23)6 / (22)3 x 25
=218 / 26 x 25
=23 x 25
=28

do you understand how combining indices works?
Original post by yolkie
can you run me through your working out for question 5, where did the 33 and 39 come from


What do you mean?

So Theres a 9 and there’s a 27 in the question and there’s also 3.

9 and 27 are both in the 3 times tables so

9x3 is 27 and 3 x 3 is 9

So 3^3 x 3^9 and then I add the powers (9 + 3) to make 3^12
Original post by Rainfall
What do you mean?

So Theres a 9 and there’s a 27 in the question and there’s also 3.

9 and 27 are both in the 3 times tables so

9x3 is 27 and 3 x 3 is 9

So 3^3 x 3^9 and then I add the powers (9 + 3) to make 3^12


3 x 3 and 33 are not the same thing
Original post by yolkie
3 x 3 and 33 are not the same thing


I wasn’t trying to prove that. I got the answer in the end so what is the issue?
Original post by Rainfall
I wasn’t trying to prove that. I got the answer in the end so what is the issue?


What did you simplify 272 to? 39?
Also 40 is 1, not 4. 41 is 4
(edited 5 years ago)
Original post by yolkie
What did you simplify 272 to? 39?


Idk cause 9 x3 is 27?
Original post by yolkie
What did you simplify 272 to? 39?
Also 40 is 1, not 4. 41 is 4


Look it again pls
BC9889E3-3100-4FE5-A140-B1A9FEE980C3.jpg.jpeg24.5KB

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