How to answer this question ?

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username3890778
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#1
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#1
Using The improper fractions method

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username3890778
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Notnek Missradioactive the improper fractions method pls
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username4036292
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#3
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#3
Sis, everything is the same as before, just turn that 9/3 to 3 because 9 divided by 3 is 3, which I'd forgotten to mention
(your book wanted a whole number + fraction)

Which part are you confused on ? Tell me particularly which part is the exact reason that this question is confusing you.

And calm down, it's okay :hugs:

I understand, when you don't get proper solution to a Math problem, it's easy to get frustrated. But doing that will confuse you even more. So it's better to take some deep breaths first
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Notnek
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(Original post by Rainfall)
Using The improper fractions method

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That's really hard to see but I'm guessing it's the same as your last question:

\displaystyle 3 \frac{2}{3} + 1 \frac{4}{5}

So the first thing you need to do is change both of those mixed numbers into improper fractions.

The way to do that for 3 \frac{2}{3} is to multiply the whole number which is the number on the left (3) by the denominator of the fraction on the right (3) then add on the numerator (2) so this gives 3 x 3 + 2 = 11.

Then you put that over the same denominator as before (3) so you get

\dfrac{11}{3}

Try doing the same with the other mixed number, 1 \frac{4}{5} and please post what you get.
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(Original post by Notnek)
That's really hard to see but I'm guessing it's the same as your last question:

\displaystyle 3 \frac{2}{3} + 1 \frac{4}{5}

So the first thing you need to do is change both of those mixed numbers into improper fractions.

The way to do that for 3 \frac{2}{3} is to multiply the whole number which is the number on the left (3) by the denominator of the fraction on the right (3) then add on the numerator (2) so this gives 3 x 3 + 2 = 11.

Then you put that over the same denominator as before (3) so you get

\dfrac{11}{3}

Try doing the same with the other mixed number, 1 \frac{4}{5} and please post what you get.
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Notnek
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(Original post by Rainfall)
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Perfect, so now you have

\displaystyle \frac{11}{3} + \frac{9}{5}

The question has changed into, "how do you add two fractions together?". Do you have any ideas how to do this? I'm thinking you've probably done it before. If you have no idea then we can guide you through it but if you have some idea please have a go and post what you've tried.
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#7
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(Original post by Notnek)
Perfect, so now you have

\displaystyle \frac{11}{3} + \frac{9}{5}

The question has changed into, "how do you add two fractions together?". Do you have any ideas how to do this? I'm thinking you've probably done it before. If you have no idea then we can guide you through it but if you have some idea please have a go and post what you've tried.
No I don’t have any idea
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Notnek
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#8
(Original post by Rainfall)
No I don’t have any idea
Okay no problem. I recommend watching a video on this because explaining a whole topic like this online could be tricky.

https://www.youtube.com/watch?v=lalcQLW6MWE

If you watch the first two mins of this videos he takes you through a similar example to your question. So try watching that and then have a go at your question. If there's anything in the video that you don't understand then please let us know.
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#9
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(Original post by Notnek)
Okay no problem. I recommend watching a video on this because explaining a whole topic like this online could be tricky.

https://www.youtube.com/watch?v=lalcQLW6MWE

If you watch the first two mins of this videos he takes you through a similar example to your question. So try watching that and then have a go at your question. If there's anything in the video that you don't understand then please let us know.
This is what I got
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Notnek
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(Original post by Rainfall)
This is what I got
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Correct Now there's one final step - you need to convert that back into a mixed number (you may not always have to do this but in this question it asks for the answer as a mixed number).

I don't know if you know how to do this. If you don't then I recommend a video again:

https://www.youtube.com/watch?v=hqxjP3lYHiQ
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username3890778
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(Original post by Notnek)
Correct Now there's one final step - you need to convert that back into a mixed number (you may not always have to do this but in this question it asks for the answer as a mixed number).

I don't know if you know how to do this. If you don't then I recommend a video again:

https://www.youtube.com/watch?v=hqxjP3lYHiQ
I don’t get the video. I have to divide 82 by 15 but the has a decimal point
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I don’t unfortunately
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Notnek
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#13
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#13
(Original post by Rainfall)
I don’t get the video. I have to divide 82 by 15 but the has a decimal point
Don’t use a calculator. You need to work out how many 15s go into 82. It doesn’t go in exactly so there will be a remainder i.e. a bit left over.

E.g. if I asked you how many 15s go into 33 then the answer is 2 (to give you 30) but with a remainder of 3.
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#14
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#14
(Original post by Notnek)
Don’t use a calculator. You need to work out how many 15s go into 82. It doesn’t go in exactly so there will be a remainder i.e. a bit left over.

E.g. if I asked you how many 15s go into 33 then the answer is 2 (to give you 30) but with a remainder of 3.
It goes in 5 times with a remainder of 7?
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Notnek
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#15
(Original post by Rainfall)
It goes in 5 times with a remainder of 7?
That’s correct. Can you now follow the method to finish the question?
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Notnek
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#16
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#16
Hi, thanks for helping but posting a full solution like this really doesn’t help a student who needs help with every part of the method. They need guidance on how to tackle each part.

Plus posting full solutions is against the rules of this forum. I hope you understand and continue to help in maths
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#17
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#17
(Original post by Notnek)
That’s correct. Can you now follow the method to finish the question?
5 7/15
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Notnek
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#18
(Original post by Rainfall)
5 7/15
Yes that's right - it took a while but you got there in the end! It's probably worth trying a few similar questions and see if you can apply the same methods. Can I ask what year you're in?
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#19
(Original post by Notnek)
Yes that's right - it took a while but you got there in the end! It's probably worth trying a few similar questions and see if you can apply the same methods. Can I ask what year you're in?
yeah I’ll do a couple more. But there are ones with subtraction .

year 13. but my understanding of maths is just bad
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hujikolp
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(Original post by Rainfall)
yeah I’ll do a couple more. But there are ones with subtraction .

year 13. but my understanding of maths is just bad
Are u resitting maths ?
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