Hard Chemistry Calculation questions anybody? GCSE standard only pls. Watch

username3961962
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Hard Chemistry Calculation questions anybody? I've got a test coming up tomorrow on GCSE chemistry calculation questions and please include answers if you have them???
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laurawatt
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Just go through past papers looking specifically for calculation questions - from lots of exam boards, not just your one
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levman2015
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Moles of Ca(OH)2 in 14.82g. Not sure if this is GCSE, but its easy A-Level stuff so i assume it would be hard GCSE.






Answer is 0.200 moles.
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username3961962
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(Original post by levman2015)
Moles of Ca(OH)2 in 14.82g. Not sure if this is GCSE, but its easy A-Level stuff so i assume it would be hard GCSE.






Answer is 0.200 moles.
Thanks-it was ok not too challenging just a simple n = m/Mr
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Sen02
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0.957mol/dm3 of H2SO4 was neutralised by 858cm3 of 0.642mol/dm3 NaOH. Calculate the volume of H2SO4 neutralised.1) Write the balanced equation. H2SO4 2NaOH → Na2SO4 2H2O2) Calculate the number of mols of NaOH. mol = concentration x volume(divide by 1000 if shown in cm3 to get dm3) =0.642*0.858=0.540564 mols of NaOH present3) Implement ratio/proportion of element. (Numbers in front of substances e.g. 2NaOH denotes 2 mols of NaOH present) NaOH2SO4 2:1 0.540564/2=0.270282 mols of H2SO4. 4) Calculate volume by using volume = mols/concentration 0.270282/0.957 = 0.2824263323dm3 of H2SO4 used
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GCSEStudent903
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If you really want to challenge, I'd strongly recommend looking at the AS-style questions. What i've seen from the new specification papers is that they're very in lieu of AS-style papers.

Have a look at OCR/AQA AS Papers for the new a level and also old a level specification. (Some questions from the very old a level specification were sampled in the new specimen papers for GCSE).

Obviously, if you see something clearly beyond what you know don't do it - but if you do want "hard" questions, they'll be a good source for you (and also the exam board making the papers).

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Sen02
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(Original post by Akshi7)
Hard Chemistry Calculation questions anybody? I've got a test coming up tomorrow on GCSE chemistry calculation questions and please include answers if you have them???
0.957mol/dm3 of H2SO4 was neutralised by 858cm3 of 0.642mol/dm3 NaOH. Calculate the volume of H2SO4 neutralised.

1) Write the balanced equation. H2SO4 + 2NaOH → Na2SO4 + 2H2O

2) Calculate the number of mols of NaOH.
mol = concentration x volume(divide by 1000 if shown in cm3 to get dm3)
=0.642*0.858=0.540564 mols of NaOH present

3) Implement ratio/proportion of element. (Numbers in front of substances e.g. 2NaOH denotes 2 mols of NaOH present)
NaOH2SO4
2:1
0.540564/2=0.270282 mols of H2SO4.

4) Calculate volume by using volume = mols/concentration 0.270282/0.957 = 0.2824263323dm3 of H2SO4 used
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entertainmyfaith
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hiya, i've moved this to chemistry for you
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username3961962
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Cheers man-guys thanks I think i'm all prepped for tomorrow. Gonna get a good night's sleep and see how it goes!
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