# Thermal physics help!

Watch
Announcements

Page 1 of 1

Go to first unread

Skip to page:

How would I do this MCQ?

You have to find the ratio between SHC and SLH?

But I’m not exactly sure how to pick up the value that is needed to plug into the formula?

Thanks

You have to find the ratio between SHC and SLH?

But I’m not exactly sure how to pick up the value that is needed to plug into the formula?

Thanks

0

reply

Report

#2

(Original post by

How would I do this MCQ?

You have to find the ratio between SHC and SLH?

But I’m not exactly sure how to pick up the value that is needed to plug into the formula?

Thanks

**Yatayyat**)How would I do this MCQ?

You have to find the ratio between SHC and SLH?

But I’m not exactly sure how to pick up the value that is needed to plug into the formula?

Thanks

Q/T = mC^T/t and

^T/t=2 so Q/T = 2Mc = P

Also Q=Ml and P=Ml/t = 2Mc time for solidification is 20 minutes

l/20 = 2cso c/l=1/40

1

reply

(Original post by

You have to assume the power stays constant so:

Q/T = mC^T/t and

^T/t=2 so Q/T = 2Mc = P

Also Q=Ml and P=Ml/t = 2Mc time for solidification is 20 minutes

l/20 = 2cso c/l=1/40

**isiaiah d**)You have to assume the power stays constant so:

Q/T = mC^T/t and

^T/t=2 so Q/T = 2Mc = P

Also Q=Ml and P=Ml/t = 2Mc time for solidification is 20 minutes

l/20 = 2cso c/l=1/40

0

reply

Report

#4

**Yatayyat**)

How would I do this MCQ?

You have to find the ratio between SHC and SLH?

But I’m not exactly sure how to pick up the value that is needed to plug into the formula?

Thanks

When the liquid is cooling, the rate of heat loss is

When the liquid is solidifying, the rate of heat loss is

Equate the two equations and you can find the required answer.

0

reply

(Original post by

Assume the rate of heat loss is constant and let rate of heat loss be P.

When the liquid is cooling, the rate of heat loss is

When the liquid is solidifying, the rate of heat loss is

Equate the two equations and you can find the required answer.

**Eimmanuel**)Assume the rate of heat loss is constant and let rate of heat loss be P.

When the liquid is cooling, the rate of heat loss is

When the liquid is solidifying, the rate of heat loss is

Equate the two equations and you can find the required answer.

0

reply

Report

#6

(Original post by

Shouldn't the second equation you put in be 'P = (M*L) / delta t, since power is the energy transferred per unit time

**Yatayyat**)Shouldn't the second equation you put in be 'P = (M*L) / delta t, since power is the energy transferred per unit time

P = \drac{m \times L \times}{\Delta t}

The correct tex should be

0

reply

X

Page 1 of 1

Go to first unread

Skip to page:

### Quick Reply

Back

to top

to top