Time of Flight of a 50Cr+ ion?
I am struggling to understand...please help?!
Q - All the psrticles have the same kinetic energy (= 0.5 mv^2) and the velocity of the particles is given by (v = d/t). If the time of flight of a 54Cr+ ion is 1.486 × 10^-5 s, calculate the time of flight of a 50Cr+ ion.
Q - All the psrticles have the same kinetic energy (= 0.5 mv^2) and the velocity of the particles is given by (v = d/t). If the time of flight of a 54Cr+ ion is 1.486 × 10^-5 s, calculate the time of flight of a 50Cr+ ion.
Thank you so much! If I understood, would this be correct? ->
54 atomic mass units = 8.966917079E-26 Kg
0.5 × 8.966917079E-26 × 67294.8 ms ^ -1 =
3.01713446E−21 Kg m^2/s
KE = 3.01713446E−21 Kg m^2/s
50 atomic mass units = 8.302700999E-26 Kg
Velocity = 3.01713446E−21 ÷ (0.5 × 8.302700999E-26) = square root of ans = 269.5892877455 m/s
1/ 269.5892877455 = 0.0037093462
-> Time of Flight = 0.0037* (2 s.f)
54 atomic mass units = 8.966917079E-26 Kg
0.5 × 8.966917079E-26 × 67294.8 ms ^ -1 =
3.01713446E−21 Kg m^2/s
KE = 3.01713446E−21 Kg m^2/s
50 atomic mass units = 8.302700999E-26 Kg
Velocity = 3.01713446E−21 ÷ (0.5 × 8.302700999E-26) = square root of ans = 269.5892877455 m/s
1/ 269.5892877455 = 0.0037093462
-> Time of Flight = 0.0037* (2 s.f)
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