The Student Room Group

Thermo: Deriving dh=Cp(dT) & du=Cv(dT)

Why does du/dT = Cv, and same for Cp?


Also, i dont understand how Cp/Cv = v, where v is the specific volume. It is derived from:
Cv + R = Cp, how is PV=nRT used to get from Cv + R = Cp to Cp/Cv = v? I know n is replaced by m/M to leave Pv=RT where R would equal R(universal gas const)/M, but how would you use that?
Thank god i took cosmology!
From Wikipedia: "Specific heat capacity, also known simply as specific heat, is the measure of the heat energy required to increase the temperature of a unit quantity of a substance by a certain temperature interval": C=dQdT \displaystyle C = \frac{dQ}{dT}

So at constant volume, the change in internal energy is equal to the heat flow into/out of the system:

dE=dQpdv=dQ dE = dQ - pdv = dQ

Cv=(ET)v \displaystyle \to C_v = \left(\frac{\partial E}{\partial T}\right)_v


At constant volume, the change in enthalpy is equal to the change in heat: dH=dQ+vdp=dQ dH = dQ + vdp = dQ

Cp=(HT)p \displaystyle \to C_p = \left(\frac{\partial H}{\partial T}\right)_p

As for the gamma factor, this is just a definition: CpCv=γ \frac{C_p}{C_v} = \gamma , I'm not sure this is a derived result, it is just a natural quantity that crops up in thermal physics.
Excellent exactly what i wanted
Oh its just perfect😇