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inequalities with modulus

how to solve
2|x| - 1 > 3|x| - 3
Use breaking of mod
Original post by DavyDG
how to solve
2|x| - 1 > 3|x| - 3


Solve the inquality for mod(x) first, then break the modulus using the fact that

mod(x) < a means -a < x < a
mod(x) > a means x < -a or x > a

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