Engineering Maths help urgent Watch

mlm1234
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#1
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how do i calculate anguled velocity
do i use standard velocity

we where going over all the standard stuff but neve covered angular but question come up and wasnt sure if she meant us to use normal because we havent covered it

is this right
find linaer velocity of the object first / radius of the object to find anuglered velocity
Last edited by mlm1234; 5 months ago
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Muttley79
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(Original post by mlm1234)
how do i calculate anguled velocity
do i use standard velocity

we where going over all the standard stuff but neve covered angular but question come up and wasnt sure if she meant us to use normal because we havent covered it

drum diameter =0.8m. mass of load 3kg, intial velocety 0m/s. time to descend 2.08s, distance traveled 0.25m. find final angular velocity and acceleration
Angular velocity is a measure of the rotational speed of an object, and is described in terms of an angle measure per unit of time, such as degrees per minute, degrees per hour, radians per minute or radians per hour.

Look up the formula
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mlm1234
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sorry just check if i got this right

find linaer velocity of the object first / radius of the object to find anuglered velocity
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Aadilkharl123
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is this about linear speed?
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mlm1234
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(Original post by Aadilkharl123)
is this about linear speed?
about final anguled velocity
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Aadilkharl123
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It is the change in angle of a moving object (measured in radians), divided by time.
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Aadilkharl123
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If v represents the linear speed of a rotating object, r its radius, and ω its angular velocity in units of radians per unit of time, then v = rω.
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mlm1234
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(Original post by Aadilkharl123)
If v represents the linear speed of a rotating object, r its radius, and ω its angular velocity in units of radians per unit of time, then v = rω.
so linear velocity divided by radius of the object
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Aadilkharl123
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(Original post by mlm1234)
so linear velocity divided by radius of the object
yes...]



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Anonymouspsych
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(Original post by mlm1234)
so linear velocity divided by radius of the object
yes
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Anonymouspsych
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The best way to think about this is simply imagining a sector of a circle with angle θ. Now imagine a point on the arc of that sector moving from one end of the arc to the other end in time t. The distance travelled = rθ so the linear speed = arc length/t = rθ/t (assuming constant speed).

I.e. v= rθ/t ===> v/r = θ/t = ω
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mlm1234
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Thank you all
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mlm1234
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(Original post by Anonymouspsych)
The best way to think about this is simply imagining a sector of a circle with angle [/font][/size]

[/font][/size]
i calulated the angular velocity
but it says calulate the final angular velocity


linear displacement /radius got the angular velocity
Vf-Vi / Tf - Ti. for final velocity
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mqb2766
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(Original post by mlm1234)
i calulated the angular velocity
but it says calulate the final angular velocity
linear displacement /radius got the angular velocity
Vf-Vi / Tf - Ti. for final velocity
If you have a question you need help with, it may help to post the full question (an image?).
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mlm1234
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calculate the final angular velocity
diameter =1m
intial v = 0s
drop time = 1.2s
drop distance = 0.2m


Linear v = 0.2/1.2 = 0.167
angular v = 0.167 /0.5 = 0.3333333
final = 0.3333 - 0/ 1.2 - 0 =0.278

is that right
what is the units for final
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mqb2766
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(Original post by mlm1234)
calculate the final angular velocity
diameter =1m
intial v = 0s
drop time = 1.2s
drop distance = 0.2m


Linear v = 0.2/1.2 = 0.167
angular v = 0.167 /0.5 = 0.3333333
final = 0.3333 - 0/ 1.2 - 0 =0.278

is that right
what is the units for final
Can you post the full question pls?
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mlm1234
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calculate the final angular velocity of the object
diameter =1m
intial v = 0s
drop time = 1.2s
drop distance = 0.2m
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mqb2766
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(Original post by mlm1234)
calculate the final angular velocity of the object
diameter =1m
intial v = 0s
drop time = 1.2s
drop distance = 0.2m
Diameter of what? There isn't enough information for this to be the full question. Units (initial v) are wrong.
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mlm1234
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calculate the final angular velocity of the object
diameter of barrel =1m
intial velocity = 0m/s
drop time = 1.2s
drop distance = 0.2m
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mqb2766
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So is the barrel falling vertically under gravity or what ... What is it rotating, why would the barrel rotate under the action of a linear force (gravity) ...?
I still don't think this is the full question. Could you please take a picture of the full question and post that picture.
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