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help maths

the question is

what is (4^2)^3 * 3^12 written in the form 6 to the power of n. I got 6 to the power of 11 because when divide by lets say 12^12/2 it will be 6^11 because u minus the powers right?.
Reply 1
how is this the same as dividing
Original post by enterbot1
the question is

what is (4^2)^3 * 3^12 written in the form 6 to the power of n. I got 6 to the power of 11 because when divide by lets say 12^12/2 it will be 6^11 because u minus the powers right?.


Misread your original expression there, ignore my last post if you saw it :smile:

Your answer is not quite correct.

Notice that the number is the same as 46312=(412)123124^{6} \cdot 3^{12} = (4^{\frac{1}{2}})^{12} \cdot 3^{12} and then 41/24^{1/2} can be simplified.

Your reasoning makes no sense though on division by 2.
Reply 3
I got up to 12^12 But the questions asks to write it in the form of 6^n so I decided to divide by 2^1 which is 6^11
Original post by enterbot1
I got up to 12^12 But the questions asks to write it in the form of 6^n so I decided to divide by 2^1 which is 6^11


That's incorrect.

Can you tell me what you simplified 41/24^{1/2} to?

[P.S. You cannot subtract from the power when you're not dividing by the same base]

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